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3 years ago

A chemical reaction is carried out in a closed container. The energy absorbed by the chemical reaction is 150 kJ.

Chemistry

1 answer:

Juliette [100K]3 years ago

7 0

Answer:

The correct answer is 150 kJ.

Explanation:

As per Law of Conservation of Energy, energy can neither be created nor destroyed, it can only change from one form to another.

If a chemical reaction absorbs 150 kJ and all the energy that is being absorbed is neither created nor destroyed, then it means all the energy absorbed comes from the surroundings (Air, wall of container etc).

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A 25.0 mLsample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5

matrenka [14]

Answer:

0.263M of CH₃COOH is the concentration of the solution.

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O

1 mole of acetic acid reacts per mole of NaOH to produce sodium acetate and water.

In the equivalence point, moles of acetic acid are equal to moles of NaOH and moles of NaOH are:

0.0375L × (0.175 moles / L) = 6.56x10⁻³ moles of NaOH = moles of CH₃COOH.

As the sample of acetic acid had a volume of 25.0mL = 0.025L:

6.56x10⁻³ moles of CH₃COOH / 0.0250L =

0.263M of CH₃COOH is the concentration of the solution

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3 years ago

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BabaBlast [244]

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2 years ago

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BaLLatris [955]

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What is the answer to the problem: 2.87 m x 12.31 m x 0.32 m?

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A certain volume of a gas had a pressure of 800 torr at a temperature of -40 degrees C. What was the original volume if the volu

nikitadnepr [17]

Answer : The original volume of gas is $365cm^3$

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 800 torr

$P_2$ = final pressure of gas at STP = 760 torr

$V_1$ = initial volume of gas = ?

$V_2$ = final volume of gas at STP = $450.0cm^3$

$T_1$ = initial temperature of gas = $-40^oC=273+(-40) =233K$

$T_2$ = final temperature of gas at STP = $0^oC=273+0=273K$

Now put all the given values in the above equation, we get:

$\frac{800torr\times V_1}{233K}=\frac{760torr\times 450.0cm^3}{273K}$

$V_1= 364.8cm^3\approx 365cm^3$

Therefore, the original volume of gas is $365cm^3$

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3 years ago