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Zielflug [23.3K]
2 years ago
14

How do wind, water, and waves cause erosion?

Physics
2 answers:
sveta [45]2 years ago
4 0

Answer:

Over time

Explanation:

When the waves crash against the rocks (erosion) small bits of rock begin to wear off. Over a lot of years lots of rock would've worn off.

valina [46]2 years ago
3 0

Answer:

when there is high wind e.g hurricane it can cause soil erosion, when there is flood it can cause soil erosion, when there are waves it can wear out the land and cause soil erosion

Explanation:

when there is high wind e.g hurricane it can cause soil erosion, when there is flood it can cause soil erosion, when there are waves it can wear out the land and cause soil erosion

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Two identical waves are traveling toward each other in the same medium. One has a positive amplitude, meaning that its peaks onl
Olin [163]
The correct answer is Destructive Interference.

Consider the image attached below. Two waves are travelling towards each other. Blue wave always has a positive peak and the red wave always has a negative peak.

Now imagine these waves are moving through a rope. If blue waves will try to move the rope in positive direction, the red wave will pull it down, and thus the two waves will cancel the effect of each other. Thus resulting in a destructive interference. 

7 0
3 years ago
Read 2 more answers
Three parallel wires each carry current I in the directions shown in (Figure 1). The separation between adjacent wires is d.
jasenka [17]

(a) The magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

(b) The magnitude of the net magnetic force per unit length on the middle wire is zero.

(c) The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

<h3>Force per unit length</h3>

The magnitude of the net magnetic force per unit length on the top wire is calculated as follows;

F₁/L = (μI₁/2π) x (I₂/d + I₃/d)

F₁/L = (μI/2π) x (I/d + I/d)

F₁/L = (μI/2π) x (2I/d)

F₁/L = μI²/πd

The magnitude of the net magnetic force per unit length on the middle wire is calculated as follows;

F₂/L = (μI₂/2π) x (I₃/d - I₁/d)

F₂/L = (μI/2π) x (I/d -  I/d) = 0

The magnitude of the net magnetic force per unit length on the middle bottom is calculated as follows;

F₃/L = (μI₂/2π) x (I₁/d + I₂/d)

F₃/L =  (μI/2π) x (I/2d + I/d)

F₃/L =  (μI/2π) x (3I/2d)

F₃/L =  3μI²/4πd

Thus, the magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

The magnitude of the net magnetic force per unit length on the middle wire is zero.

The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

Learn more about magnetic force here: brainly.com/question/13277365

#SPJ1

6 0
2 years ago
Does the car's<br> speed alone<br> determine<br> whether the egg<br> breaks?
blsea [12.9K]

Answer:

yes it is

Explanation:

when the speed increases the car will vibration than egg will breaks

4 0
2 years ago
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What is the force of friction acting on the crate? I am offering 30 points.
olganol [36]
I think the answer is C


4 0
2 years ago
A Car is moving at a speed of 20 m/s. How Much Distance it will cover in 1 min? Express the answer in km.
natita [175]

Answer:

d=20m/sx60s=1200m=1200/1000Km=1.2km

Explanation:

8 0
2 years ago
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