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Zielflug [23.3K]
3 years ago
14

How do wind, water, and waves cause erosion?

Physics
2 answers:
sveta [45]3 years ago
4 0

Answer:

Over time

Explanation:

When the waves crash against the rocks (erosion) small bits of rock begin to wear off. Over a lot of years lots of rock would've worn off.

valina [46]3 years ago
3 0

Answer:

when there is high wind e.g hurricane it can cause soil erosion, when there is flood it can cause soil erosion, when there are waves it can wear out the land and cause soil erosion

Explanation:

when there is high wind e.g hurricane it can cause soil erosion, when there is flood it can cause soil erosion, when there are waves it can wear out the land and cause soil erosion

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In what order does light pass through structures of the eye? lens, cornea, retina cornea, pupil, lens pupil, iris, lens pupil, c
Mrrafil [7]

Answer: Light passes through the front of the eye (cornea) to the lens. The cornea and the lens help to focus the light rays onto the back of the eye (retina). The cells in the retina absorb and convert the light to electrochemical impulses which are transferred along the optic nerve and then to the brain.

Explanation:

When light rays reflect off an object and enter the eyes through the cornea (the transparent outer covering of the eye), you can then see that object. The cornea bends, or refracts, the rays that pass through the round hole of the pupil.

4 0
3 years ago
A positive charge of 3.2 x 10 -5 C is located 0.85 m away from another positive charge of 7.4 x 10 -6 C. What is the electric fo
zmey [24]

by using Coulumbs Law its 2.95N.

7 0
3 years ago
A sphere of metal has a mass of 1431 g and a diameter of 5.80 cm. What is the density of metal in g/cm3
Dmitriy789 [7]

Answer:

see below

Explanation:

You will need t find the volume of the sphere

 4/3 pi r^3    divide into the mass

1431 / (4/3 pi (5.8)^3) = 14 gm /cm^3

4 0
2 years ago
What is a conclusion?
Vikki [24]
The end or finish of an event or process.
8 0
2 years ago
Read 2 more answers
Before beginning a long trip on a hot day, a driver inflates anautomobile tire to a gauge pressure of 2.70 atm at 300 K. At the
anygoal [31]

Answer:

The value is the temperature of the air inside the tire T_{2} = 340.54 K

% of the original mass of air in the tire should be released 99.706 %

Explanation:

Initial gauge pressure = 2.7 atm

Absolute pressure at inlet P_{1} = 2.7 + 1 = 3.7 atm

Absolute pressure at outlet P_{2} = 3.2 + 1 = 4.2 atm

Temperature at inlet T_{1} = 300 K

(a) Volume of the system is constant so  pressure is directly proportional to the temperature.

\frac{T_{2} }{T_{1} } = \frac{P_{2} }{P_{1} }

\frac{T_{2} }{300}  = \frac{4.2}{3.7}

T_{2} = 340.54 K

This is the value is the temperature of the air inside the tire

(b). Since volume of the tyre is constant & pressure reaches the original value.

From ideal gas equation P V = m R T

Since P , V & R is constant. So

m T = constant

m_{1}  T_{1} =  m_{2}  T_{2}

\frac{m_{2} }{m_{1}  } = \frac{T_{1} }{T_{2} }

\frac{m_{2} }{m_{1}  } = \frac{300}{354.54}

\frac{m_{2} }{m_{1}  } =0.00294

value of  the original mass of air in the tire should be released is  \frac{m_{2} - m_{1}}{m_{1}}

\frac{0.00294-1}{1}

⇒ -0.99706

% of the original mass of air in the tire should be released 99.706 %.

8 0
2 years ago
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