2 years ago

Compare the momentum of a 7160 kg truck moving at 5.00 m/s to the

Physics

1 answer:

Bess [88]2 years ago

3 0

Answer:

2,200

Explanation:

truck=35800,car=33600

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A 15.0-kg child descends a slide 2.40 m high and reaches the bottom with a speed of 1.10 m/s .

pickupchik [31]

The thermal energy that is generated due to friction is 344J.

<h3>What is the thermal energy?</h3>

Now we know that the total mechanical energy in the system is constant. The loss in energy is given by the loss in energy.

Thus, the kinetic energy is given as;

KE = 0.5 * mv^2 =0.5 * 15.0-kg * (1.10 m/s)^2 = 9.1 J

PE = mgh = 15.0-kg * 9.8 m/s^2 * 2.40 m = 352.8 J

The thermal energy is; 352.8 J - 9.1 J = 344J

Learn more about thermal energy due to friction:brainly.com/question/7207509

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2 years ago

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I need the answer too

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Identify the subordinate clause and tell if it is used as a noun, adjective, or adverb. Click on the blue box until the correct

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3 years ago

if the 50 kg object slows down to a velocity of 1 m/s how much kinetic energy does it have 100j 50j 25j or none

rodikova [14]

$ek = \frac{1}{2}m {v}^{2}$

$ek = \frac{1}{2}(50) {(1)}^{2}$

$ek = \frac{1}{2}(50)$

$ek = 25j$

I'm not really sure but I do know that it's not 0 because the object is still moving, even if it's only moving at 1 m/s.

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3 years ago

A gas in a sealed container has a pressure of 50 kPa at 27°C. What will the pressure of the gas be if the temperature rises to 8

alexgriva [62]

Answer:

the final pressure of the gas is 60 kPa.

Explanation:

Given;

initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa

initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k

final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K

Let the final pressure of the gas = P₂

Apply pressure law;

$\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} = \frac{50,000 \times 360}{300} = 60,000 \ Pa = 60 \ kPa$

Therefore, the final pressure of the gas is 60 kPa.

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3 years ago