1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bogdanovich [222]
3 years ago
10

If the concentration of Ag+ is 0.0115 M, the concentration of H+ is 0.355 M, and the pressure of H2 is 1.00 atm, calculate the c

ell potential at 25.0°C. The standard reduction potentials are: $$ Eo = 0.80 V $$ Eo = 0.00 V
Physics
1 answer:
scoundrel [369]3 years ago
4 0

<u>Answer:</u> The cell potential is 0.712 V

<u>Explanation:</u>

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, silver will undergo reduction reaction will get reduced. Hydrogen will undergo oxidation reaction and will get oxidized

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> H_2(1.00atm)\rightarrow 2H^{+}(0.355M)+2e^-;E^o_{H^{+}/H_2}=0.00V

<u>Reduction half reaction:</u> Ag^{+}(0.0115M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V   ( × 2 )

<u>Net reaction:</u> H_2(1.00atm)+2Ag^{+}(0.0115M)\rightarrow 2H^{+}(0.355M)+2Ag(s)

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=0.80-(0.00)=0.80V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^2}{[Ag^{+}]^2}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = +0.80 V

n = number of electrons exchanged = 2

[Ag^{+}]=0.0115M

[H^{+}]=0.355M

Putting values in above equation, we get:

E_{cell}=0.80-\frac{0.059}{2}\times \log(\frac{(0.355)^2}{(0.0115)^2})\\\\E_{cell}=0.712V

Hence, the cell potential is 0.712 V

You might be interested in
Question 11 of 15
SVEN [57.7K]
Carbon tetrahydride is B. CH4
5 0
3 years ago
Read 2 more answers
A weather balloon is partially inflated with helium gas to a volume of 2.0 m³. The pressure was measured at 101 kPa and the temp
Yanka [14]

Answer:

4.7 m³

Explanation:

We'll use the gas law P1 • V1 / T1 = P2 • V2 / T2

* Givens :

P1 = 101 kPa , V1 = 2 m³ , T1 = 300.15 K , P2 = 40 kPa , T2 = 283.15 K

( We must always convert the temperature unit to Kelvin "K")

* What we want to find :

V2 = ?

* Solution :

101 × 2 / 300.15 = 40 × V2 / 283.15

V2 × 40 / 283.15 ≈ 0.67

V2 = 0.67 × 283.15 / 40

V2 ≈ 4.7 m³

7 0
2 years ago
Two identical bowling balls are rolling on a horizontal floor without slipping. The initial speed of both balls is v = 10 m/s. B
Lapatulllka [165]

Answer:

The difference between frictionless ramp and a regular ramp is that on a frictionless ramp the ball cannot roll it can only slide, but on a regular ramp the ball can roll without slipping.

We will use conversation of energy.

K_A_1 + U_A_1 = K_A_2 + U_A_2\\\frac{1}{2}I\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_A

Note that initial potential energy is zero because the ball is on the bottom, and the final kinetic energy is zero because the ball reaches its maximum vertical distance and stops.

For the ball B;

K_B_1 + U_B_1 = K_B_2 + U_B_2

\frac{1}{2}I_B\omega^2 + \frac{1}{2}mv^2 + 0 = 0 + mgH_B

The initial velocities of the balls are equal. Their maximum climbing point will be proportional to their final potential energy. Since their initial kinetic energies are equal, their final potential energies must be equal as well.

Hence, both balls climb the same point.

Explanation:

4 0
3 years ago
A +6.33 uC charge q1 is attracted by a force of 0.115 N to a second charge q2 that is 1.44 m away. What is the value of q2?
jarptica [38.1K]

Answer:-4.1858

Explanation: I hate Acellus

7 0
2 years ago
How to change this to mega and giga prefixes?urgent .thankyou
Akimi4 [234]
3*10^{8} m = 3*10^{5} km = 3*10^{2} Mm = 3*10^{-1} Gm

Each increase in the prefix is a division by 1000.
6 0
3 years ago
Other questions:
  • How would Newton's Three laws apply to a Ferris Wheel?
    10·1 answer
  • Which scenario best describes motion? a toy train in position 4 on a number line a race track that is 100 meters long a ball rol
    12·2 answers
  • What must the charge (sign and magnitude) of a particle of mass 1.49 g be for it to remain stationary when placed in a downward-
    15·1 answer
  • The acceleration of a baseball pitcher's hand as he delivers a pitch is extreme. For a professional player, this acceleration ph
    10·1 answer
  • Which of the following statements is a true statement about the use of nuclear energy as an alternative energy source?
    11·1 answer
  • Which factors affect the resistance of a material? Check all that apply.
    5·1 answer
  • A 5.83 kg object is released from rest while fully submerged in a liquid. The liquid displaced by the submerged object has a mas
    5·1 answer
  • A railroad car moving at a speed of 3.46 m/s overtakes, collides and couples with two coupled railroad cars moving in the same d
    13·1 answer
  • A rocket is traveling toward the earth at 12c when it ejects a missile forward at 12c relative to the rocket.
    13·1 answer
  • 5. Find the velocity of a train that traveled 75 km in 35 minutes. (answer
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!