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Tanya [424]
3 years ago
6

A 10.1 g bullet leaves the muzzle of a rifle with a speed of 558.4 m/s. what constant force is exerted on the bullet while it is

traveling down the 0.7 m length of the barrel of the rifle? answer in units of n
Physics
1 answer:
artcher [175]3 years ago
6 0
To answer any question to do with mass, acceleration, velocity (etc...) you use one or more of this set of equations. They are called the 'Kinematic' equations and are really easy to re-arrange, when you need to find the 'unknown quantity' that the question is asking for. Below these equations i will show you the general problem solving strategy to very quickly and easily solve these problems.

The Kinematic Equations

D = (v_{i} * t) + (0.5 * a * t^2)
v_{f} ^2 = v_{i}^2 + (2 * a * D)
v_{f} = v_{i} + (a*t)
D =  (\frac{v_{i} + v_{f}}{2} ) * t

The Method

1. 
Write down all the known variables and their values + the one you don't know with a question mark next to it. (v = ?)

2. Find the kinematic equation where you have ALL the variables <span>except</span> the one you are missing.

3. Re-arrange the equation to solve for the missing variable.

Done!

<span>HINT: Sometimes you need to use two kinematic equations, one after the other, in order to get the answer. It is common for questions to not give two variables, like velocity AND acceleration to force you to solve for one, then use that solution in another kinematic equation to finally solve the problem. Writing down the known variables is the fastest way to see what you have and what you need.
____________________________________________

</span>This question takes things one step further and is asking you to find the FORCE on the bullet. To convert to a force in any situation you need to find the <span>acceleration</span> and multiply it by the mass as follows:

F = m * a

<em>Remember this equation!! you will use it ALL the time.

</em>Please let me know if you still cannot solve this problem, but i believe you should be fine :)<em>
</em>
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When a car slows down suddenly, passengers in the car tend to move toward the front of the car. What is this due to?
Neko [114]
Hey there Kendrell!

Yes, this is very true, when the car slows down, our bodies will tend to lean forward a little bit, and this is actually due to the "motion of inertia".

Inertia allows for this to happen, this is why in this case, we have this case.

Hope this helps.
~Jurgen


4 0
3 years ago
A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the centripetal
Lynna [10]

Wow !  This will take more than one step, and we'll need to be careful
not to trip over our shoe laces while we're stepping through the problem.

The centripetal acceleration of any object moving in a circle is

                          (speed-squared)  /  (radius of the circle)  .

Notice that we won't need to use the mass of the train.

We know the radius of the track.  We don't know the trains speed yet,
but we do have enough information to figure it out.  That's what we
need to do first.

Speed  =  (distance traveled) / (time to travel the distance).

Distance = 10 laps of the track.   Well how far is that ? ? ?

1 lap = circumference of the track = (2π) x (radius) =  2.4π  meters

10 laps =  24π  meters.

Time = 1 minute 20 seconds  =  80 seconds

The trains speed is  (distance) / (time)

                               =  (24π meters) / (80 seconds)

                               =        0.3 π  meters/second .

NOW ... finally, we're ready to find the centripetal acceleration.

                                 <span> (speed)²  /  (radius)

                           =    (0.3π m/s)²  /  (1.2 meters)

                           =    (0.09π m²/s²)  /  (1.2 meters)

                           =    (0.09π  /  1.2)   m/s²

                           =          0.236  m/s²  .        (rounded)

If there's another part of the problem that wants you to find
the centripetal FORCE ...

Well,       Force = (mass) · (acceleration) .

We know the mass, and we ( I ) just figured out the acceleration,
so you'll have no trouble calculating the centripetal force.       </span>
4 0
3 years ago
A runner accelerates toward the finish line.
Brut [27]
C the runners feet pushing against the ground describes the acceleration toward the finish line
6 0
3 years ago
Ice-skater slides toward a sled sitting on the ice and hits it. The skater exerts a 12.6 N force on the sled at an angle of 15.3
RideAnS [48]

Answer:

Expression of work done is

W = Fd cos\theta

Work done to move the sled is given as 187.2 J

Explanation:

As we know that the formula of work done is given as

W = Fd cos\theta

here we know that

F = 12.6 N

d = 15.4 m

\theta = 15.3 degree

so we will have

W = 12.6 \times 15.4 cos15.3

W = 187.2 J

5 0
3 years ago
Which countries that had sea ice along their coasts in September 1986 were bordered by open water in September 2017?
mrs_skeptik [129]

Answer:

Norway, Sweden, Finland and Iceland

Explanation:

Sea ice is a frozen seawater that floats on the ocean surface. It is formed between the Antarctic and Arctic hemisphere. It disappears in summer but not completely. The countries that experienced sea ice in 1986 were eight (8) in number but the countries bordered by open water were in September 2017 were Norway, Iceland, Finland and Russia.

5 0
3 years ago
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