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Tanya [424]
4 years ago
6

A 10.1 g bullet leaves the muzzle of a rifle with a speed of 558.4 m/s. what constant force is exerted on the bullet while it is

traveling down the 0.7 m length of the barrel of the rifle? answer in units of n
Physics
1 answer:
artcher [175]4 years ago
6 0
To answer any question to do with mass, acceleration, velocity (etc...) you use one or more of this set of equations. They are called the 'Kinematic' equations and are really easy to re-arrange, when you need to find the 'unknown quantity' that the question is asking for. Below these equations i will show you the general problem solving strategy to very quickly and easily solve these problems.

The Kinematic Equations

D = (v_{i} * t) + (0.5 * a * t^2)
v_{f} ^2 = v_{i}^2 + (2 * a * D)
v_{f} = v_{i} + (a*t)
D =  (\frac{v_{i} + v_{f}}{2} ) * t

The Method

1. 
Write down all the known variables and their values + the one you don't know with a question mark next to it. (v = ?)

2. Find the kinematic equation where you have ALL the variables <span>except</span> the one you are missing.

3. Re-arrange the equation to solve for the missing variable.

Done!

<span>HINT: Sometimes you need to use two kinematic equations, one after the other, in order to get the answer. It is common for questions to not give two variables, like velocity AND acceleration to force you to solve for one, then use that solution in another kinematic equation to finally solve the problem. Writing down the known variables is the fastest way to see what you have and what you need.
____________________________________________

</span>This question takes things one step further and is asking you to find the FORCE on the bullet. To convert to a force in any situation you need to find the <span>acceleration</span> and multiply it by the mass as follows:

F = m * a

<em>Remember this equation!! you will use it ALL the time.

</em>Please let me know if you still cannot solve this problem, but i believe you should be fine :)<em>
</em>
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A TV set is pushed a distance of 2 m with a force of 20 N how much work is done on the set ​
vladimir2022 [97]

Answer:

40 J

Explanation:

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3 years ago
In the national grid,what does the step up transformer do?
amm1812
In the National Grid, the Step Up Transformer increases the amount of voltage that is passing through the grid at any one time. These are used at power stations, as without them, there would not be enough power to transport the electricity around the national grid.
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Find the electron and hole concentrations and fermi level in silicon at 300 k for boron
gogolik [260]

To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x 10^4 cm^-3.

<h3>Calculation and Explanation</h3>

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at 10^{15} cm^{-3} (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = 10^{15} cm^{-3}

np = \frac{ni^2}{nA}

np = \frac{(9.65 x 10^9)^2}{10^15}

np= 9.3 x 10^4 cm^-3

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x 10^{19} / 10^{15} )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

What is ionization energy?

Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

To know more about ionization energy, visit:

brainly.com/question/16243729

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4 0
1 year ago
A spring of constant 20 N/m has compressed a distance 8 m by a(n) 0.3 kg mass, then released. It skids over a frictional surface
Fiesta28 [93]

Answer:

X_2=25.27m

Explanation:

Here we will call:

1. E_1: The energy when the first spring is compress

2. E_2: The energy after the mass is liberated by the spring

3. E_3: The energy before the second string catch the mass

4. E_4: The energy when the second sping compressed

so, the law of the conservations of energy says that:

1. E_1 = E_2

2. E_2 -E_3= W_f

3.E_3 = E_4

where W_f is the work of the friction.

1. equation 1 is equal to:

\frac{1}{2}Kx^2 = \frac{1}{2}MV_2^2

where K is the constant of the spring, x is the distance compressed, M is the mass and V_2 the velocity, so:

\frac{1}{2}(20)(8)^2 = \frac{1}{2}(0.3)V_2^2

Solving for velocity, we get:

V_2 = 65.319 m/s

2. Now, equation 2 is equal to:

\frac{1}{2}MV_2^2-\frac{1}{2}MV_3^2 = U_kNd

where M is the mass, V_2 the velocity in the situation 2, V_3 is the velocity in the situation 3, U_k is the coefficient of the friction, N the normal force and d the distance, so:

\frac{1}{2}(0.3)(65.319)^2-\frac{1}{2}(0.3)V_3^2 = (0.16)(0.3*9.8)(2)

Volving for V_3, we get:

V_3 = 65.27 m/s

3. Finally, equation 3 is equal to:

\frac{1}{2}MV_3^2 = \frac{1}{2}K_2X_2^2

where K_2 is the constant of the second spring and X_2 is the compress of the second spring, so:

\frac{1}{2}(0.3)(65.27)^2 = \frac{1}{2}(2)X_2^2

solving for X_2, we get:

X_2=25.27m

3 0
3 years ago
One car travels 56 meters due east in 2.0 seconds, and a second car travels 84 meters due west in 3.0 seconds. During their peri
Lubov Fominskaja [6]

Answer:

  average speed

Explanation:

The directions were different, so the velocities could not be the same.

However, the magnitude of the velocity (speed) was 56/2 = 28 m/s for the first car, and 84/3 = 28 m/s for the second car. These<em> average speeds are the same</em>.

5 0
3 years ago
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