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Tanya [424]
3 years ago
6

A 10.1 g bullet leaves the muzzle of a rifle with a speed of 558.4 m/s. what constant force is exerted on the bullet while it is

traveling down the 0.7 m length of the barrel of the rifle? answer in units of n
Physics
1 answer:
artcher [175]3 years ago
6 0
To answer any question to do with mass, acceleration, velocity (etc...) you use one or more of this set of equations. They are called the 'Kinematic' equations and are really easy to re-arrange, when you need to find the 'unknown quantity' that the question is asking for. Below these equations i will show you the general problem solving strategy to very quickly and easily solve these problems.

The Kinematic Equations

D = (v_{i} * t) + (0.5 * a * t^2)
v_{f} ^2 = v_{i}^2 + (2 * a * D)
v_{f} = v_{i} + (a*t)
D =  (\frac{v_{i} + v_{f}}{2} ) * t

The Method

1. 
Write down all the known variables and their values + the one you don't know with a question mark next to it. (v = ?)

2. Find the kinematic equation where you have ALL the variables <span>except</span> the one you are missing.

3. Re-arrange the equation to solve for the missing variable.

Done!

<span>HINT: Sometimes you need to use two kinematic equations, one after the other, in order to get the answer. It is common for questions to not give two variables, like velocity AND acceleration to force you to solve for one, then use that solution in another kinematic equation to finally solve the problem. Writing down the known variables is the fastest way to see what you have and what you need.
____________________________________________

</span>This question takes things one step further and is asking you to find the FORCE on the bullet. To convert to a force in any situation you need to find the <span>acceleration</span> and multiply it by the mass as follows:

F = m * a

<em>Remember this equation!! you will use it ALL the time.

</em>Please let me know if you still cannot solve this problem, but i believe you should be fine :)<em>
</em>
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I can’t figure it out! <br> Please help I have a test tomorrow
nignag [31]

it's 20m/s i.e. no. (2)


7 0
3 years ago
A cannonball is fired horizontally at the same time a ball being dropped from the same height How do the times it takes them to
ipn [44]

Answer:

The cannonball and the ball will both take the same amount of time before they hit the ground.

Explanation:

For a ball fired horizontally from a given height, there is only a vertical acceleration on it towards the ground. This acceleration is equal to the acceleration due to gravity (g = 9.81 m/s^2). A ball dropped from a height will also only experience the same vertical acceleration downwards which is also equal to g = 9.81 m/s^2.

Therefore both the cannonball and the ball will take the same amount of time to hit the ground if they are released/fired from the same height.

3 0
3 years ago
1. Add 17.35 g, 25.6 g and 8.498 g. chaper 1 physical quantity 11class .physic​
Korvikt [17]

51.448 g is the required answer!

8 0
3 years ago
A student is walking back up the hill from the field to the school building. His
myrzilka [38]

Answer:

Time cause it's so long ago I was just

4 0
3 years ago
A pendulum is made by letting a 2.0-kg object swing at the end of a string that has a length of 2.1 m. The maximum angle the str
just olya [345]

Answer:

The speed of the object at the lowest point in its trajectory is:

v=2.34\: m/s

Explanation:

We can use the conservation of energy between the maximum point of swing and the lowest point of the pendulum.

P=K

mgh=\frac{1}{2}mv^{2} (1)

Where:

  • h is the height of the object at 30° with the vertical.
  • v is the speed at the lowest point.

We can find h using trigonometry.

h=L-Lcos(30)=L(1-cos(30))

h=2.1(1-cos(30))=0.28\: m

Now, using equation (1) we can find v.

gh=\frac{1}{2}v^{2}

2gh=v^{2}

v=\sqrt{2gh}

v=\sqrt{2(9.81)(0.28)}

v=2.34\: m/s

I hope it helps you!

8 0
2 years ago
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