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nikdorinn [45]
3 years ago
7

How can you tell if a compound contains a polyatomic ion because the entire compound has?

Chemistry
1 answer:
gayaneshka [121]3 years ago
6 0
brainly.com/question/8469892#respond
You might be interested in
BRAINLIEST TO FIRST CORRECT ANSWER, THANKS!
Tamiku [17]

Answer:

increased

Explanation:

Consuming a compound increases the concentration. When you increase the concentration, the rate constant for that reaction also increases.

5 0
4 years ago
When Silver (Ag) forms a metallic bond with other Silver atoms, what do the valence electrons move into? A. the all go to the sa
Korolek [52]

Answer:

D. the sea of electrons

Explanation:

Metallic bonds are defined as the bonds formed between two or more metals. Silver atom form metallic bond with other silver atoms.

In metallic bond, the free electrons or valence electrons present in s and p orbitals delocalize. The valence electrons do not move around the atoms or enter the atoms whereas they form a sea of electrons in which they surround the nuclei (positively charged) of the metal ions interacting. The valence electrons are then freely move in the space between the atomic nuclei.

Hence, the correct answer is "D. the sea of electrons".

7 0
4 years ago
3. What do platelets do?
PolarNik [594]

Answer:

C help stop bleeding

Explanation:

Platelets stop bleeding by clumping and forming plugs in blood vessel injuries

5 0
3 years ago
Determine the empirical formula of a compound containing 8.56 g silicone of 43.2 g of chlorine
SpyIntel [72]

The empirical formula of the compound is SiCl₄.

<h3>Empirical formula of the compound</h3>

mass of silicon = 28 g/mol

mass of chlorine = 35.5 g/mol

<h3>molar ration: </h3>

Si = 8.56/28   =  0.306

Cl = 43.2/35.5  = 1.216

<h3>Combining ratio</h3>

Si = 0.306/0.306 = 1

Cl = 1.216/0.306 = 4

empirical formula = SiCl₄

Thus, the empirical formula of the compound is SiCl₄.

Learn more about empirical formula here: brainly.com/question/1603500

#SPJ1    

6 0
2 years ago
What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution (Na = 23 g; S = 32 g; O = 16 g)
Leno4ka [110]

Answer:

852g

Explanation:

From the question given, we obtained the following information:

Molarity = 3M

Volume = 2L

Mole =?

First, we need to find the number of mole of Na2SO4 present in 2L of the solution. This is achieved by doing the following:

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 3 x 2 = 6moles

Next, we'll find the molar mass of Na2SO4, as illustrated below:

Molar Mass of Na2SO4 = (23x2)+32+(16x4) = 46 + 32 + 64 = 142g/mol

Recall:

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass = 6 x 142 = 852g

8 0
3 years ago
Read 2 more answers
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