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Blizzard [7]
3 years ago
15

which occupies a larger volume, 600 g of water (with a density of 0.995 g/cm3 ) or 600 g of lead (with a density of 11.35 g/cm3

)? energy units
Chemistry
1 answer:
Montano1993 [528]3 years ago
5 0
Water will occupy larger volume
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Question 34 (1 point)
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Answer:

8.33 atm

Explanation:

Xe is   5  out of (4+5)   or   5 / 9 ths of the gas present

  5/9  * 15 atm = 8.33 atm

4 0
1 year ago
The mass of an atom may be found by adding the
Darina [25.2K]

Answer:

protons and neutrons

Explanation:

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2 years ago
Read the chemical equation.
WARRIOR [948]

Answer:

One mole of water was produced from this reaction.

Explanation:

According to this question, the following equation is given as follows:

2H2 + O2 → 2H2O

Two (2) moles of hydrogen gas produces two (2) moles of water in this balanced chemical equation.

If 1 mole of hydrogen gas was used, then:

1 × 2/2 moles of water would be produced

1 mole of water would be produced.

3 0
3 years ago
Alguien sabe el nombre del compuesto etilisopropilacetileno?​
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3 0
3 years ago
When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu
Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0
3 years ago
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