All categories

3 years ago

How to find effective nuclear charge

Chemistry

1 answer:

kiruha [24]3 years ago

3 0

The effective nuclear charge is the net positive charge experienced by valence electrons

You might be interested in

What is the oxidation number for zinc? How does zinc's electron configuration account for this oxidation number?

IRINA_888 [86]

+2 is the oxidation number for Zinc
<span>Oxidation Number for a Transition metal = Number of Unpaired d-electrons + Two s-electrons
</span>[Ar]4s2 3d10 is the electron configuration for zinc. The d-block is full with 10 electrons meaning there are no unpaired d-electrons, so the oxidation number is 0 unpaired d-electrons + 2 s-electrons = +2

8 0

2 years ago

Which class of organic compounds has molecules that contain nitrogen atoms?

ziro4ka [17]

2) amine is the correct answer

7 0

3 years ago

Compute the following and give your answer on scientific notation

Nata [24]

Answer:

6*10^-3

Hope it helps

Procedure in the attached file

4 0

3 years ago

An electric current is applied to a 1.0 m nai solution. (i) write the balanced oxidation half reaction for the reaction that tak

MakcuM [25]

Answers are:
1) The balanced oxidation half reaction: 2I⁻(aq) → I₂(s) + 2e⁻.
Iodine is oxidized (lost electrons) from -1 to neutral charge (0).
2) The balanced reduction half-reaction: 2H₂O(l) + 2e⁻ → H₂(g) + 2OH⁻.
Hydrogen is reduced (gain electrons) from +1 to neutral charge.
3) The oxidation <span>reaction takes place at the anode.</span>

5 0

3 years ago

How much heat must be removed from 456 g of water at 25. 0 c to hcange it into ice at 10 c

ValentinkaMS [17]

The heat required to convert water is given as the product of the mas and the latent heat. 28.34 kJ heat must be removed from the water to change it into ice.

<h3>What is heat energy?</h3>

Heat energy is the product of mass, specific heat capacity, and temperature change. It is given as,

$\rm Q = mc \Delta T$

Given,

Mass of water = 456 gm

Specific heat capacity = 4.186 J / g K

Temperatutre change = 14.85 K

Substituting values above:

$\begin{aligned} \rm Q &= 456 \times 4.186 \times 14.85\\\\&= 28345.91\;\rm J\\\\&= 28.34\;\rm kJ\end{aligned}$

Therefore, 28.34 kJ of heat energy should be removed from the water.

Learn more about the heat here:

brainly.com/question/14052023

#SPJ4

6 0

2 years ago