1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
3 years ago
9

The density of water is 1.00 g/ml at 4°c. how many water molecules are present in 2.56 ml of water at this temperature?

Chemistry
1 answer:
o-na [289]3 years ago
5 0

Answer:

             8.55 × 10²² Molecules

Solution:

Step 1: Calculate the Mass of Water as;

                       Density  =  Mass ÷ Volume

Solving for Mass,

                       Mass  =  Density × Volume

Putting values,

                       Mass  =  1 g.mL⁻¹ × 2.56 mL

                       Mass  =  2.56 g

Step 2: Calculate Moles of Water as,

                       Moles  =  Mass ÷ M.Mass

Putting values,

                       Moles  =  2.56 g ÷ 18 g.mol⁻¹

                       Moles  =  0.142 mol

Step 3: Calculate Number of Molecules of Water as,

                       # of Molecules  =  Moles × 6.022 × 10²³

Putting value of mole,

                       # of Molecules  =  0.142 × 6.022 × 10²³

                       # of Molecules  =  8.55 × 10²² Molecules

You might be interested in
Please assist me with chemistry assessment
Lera25 [3.4K]

Answer:

I don't know

Explanation:

7 0
1 year ago
The empirical formula of styrene is CH; its molar mass is 104.1 g/mol. What is the molecular formula of styrene?
Natalija [7]
You got the answer correct. If you would double check
given:C (12 g/mol) H (1 g/mol). 

12(8) + 1(8) = 104 g/mol

and for C2H4
12(2)+1(4) = 28g/mol

Also, chemical formula of styrene is<span> C6H5CH=CH2.</span>
7 0
3 years ago
Read 2 more answers
The protein lysozyme unfolds at a transition temperature of 75.5°C, and the standard enthalpy of transition is 509 kJ mol-1. Cal
spin [16.1K]

Answer:

0.4774 KJ/K.mol

Explanation:

We are told that the transition at 25.0°C occurs in three steps. Steps i, ii and iii.

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii

Now,

C_p,m(unfolded protein) = C_p,m(folded protein) + 6.28 kJ/K.mol

Now, for the first process, ΔS_i is given as;

ΔS_i = C_p,m × In(T2/T1)

We are given;

T1 = 25°C = 25 + 273.15K = 298.15 K

T2 = 75.5°C = 75.5 + 273.15 K=348.65 K

Thus;

ΔS_i = C_p,m × In(348.65/298.15)

Now, for the third process, ΔS_iii is given as;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(T1/T2)

Thus;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)

Now, we don't know C_pm. So, we have to find a way to eliminate it. We will do it by rewriting In(298.15/348.65) in such a way that when ΔS_iii is added to ΔS_i, C_p,m will cancel out. Thus;

In(298.15/348.65) can also be written as;

In(348.65/298.15)^(-1) or

- In(348.65/298.15)

Thus;

ΔS_iii = - [(C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)]

Now, let's add ΔS_iii to ΔS_i to get;

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] + [(-C_p,m - 6.28 kJ/K.mol) × In(348.65/298.15)]

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] - [C_p,m × In(348.65/298.15)] - [6.28In(348.65/298.15)]

First 2 terms will cancel out to give;

ΔS_i + ΔS_iii = -6.28In(348.65/298.15)

ΔS_i + ΔS_iii = -0.9826 KJ/K.mol

Now,for process ii;

ΔS_ii = standard enthalpy of transition/Transition Temperature

Thus;

ΔS_ii = (509 KJ/K.mol)/348.65

ΔS_ii = 1.46 KJ/K.mol

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii = -0.9826 + 1.46 = 0.4774 KJ/K.mol

5 0
3 years ago
(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial
icang [17]

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

3 0
3 years ago
Which of the following is accurate in describing the placement and classification of iodine?
fenix001 [56]
You can answer this question by only searching the element in the periodic table.

The atomic number of iodine, I, is 53. It is placed in the column 17 (this is the Group) and row 5 (this is the Period).

The conclusion is that the iodine is located in Period 5, Group 17, and is classified as a nonmetal.
4 0
3 years ago
Other questions:
  • What is the chemical formula for iron (III) bicarbonate?
    12·1 answer
  • What term expresses the ratio of moles of reactants and products according to the coefficients in the balanced chemical equation
    14·1 answer
  • What is 9.871 x 10^-3 in standard form? *
    14·2 answers
  • During a chemical reaction, the atom of the substances are _____ to form new or different substances
    14·1 answer
  • HNS + O2 =<br><br> How do I balance this equation?
    15·2 answers
  • How many moles of solute are in 9.03 M solution with 15.8 L of solution?
    5·1 answer
  • An unbalanced chemical equation is shown: 2NaN3 → 2Na + N2 Which of the following statements explains why the equation is not ba
    11·2 answers
  • Hurry I need the answer asap
    11·1 answer
  • Which statement best describes the movement of energy?.
    9·1 answer
  • Transcribe and translate the following DNA sequence:
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!