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kow [346]
3 years ago
7

A piece of copper has a volume 130 L. What is the mass of the sample, in units of kilograms?

Chemistry
1 answer:
Reil [10]3 years ago
3 0

Answer: The mass of the sample is 1264.800 kg.

Explanation:

Mass of the piece of copper = m

Volume of the copper price = 130 L=130,000 cm^3

1 L= 1,000 cm^3

Density=8.96 g/cm^3=\frac{Mass}{Volume}=\frac{Mass}{130,000 cm^3}

m=Density\times Volume=8.96 g/cm^3\times 130,000=1,264,800 g

m = 1,264,800 g = 1,264.800 kg (1 kg = 1000 g)

The mass of the sample is 1264.800 kg.

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What three parts make up an atom?
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The nucleus of an atom is made up of protons and neutrons. Then electrons circle around the nucleus.

Answer:

Proton, Neutron, Electron

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A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask "S" to a 25.00 mL volumetric flask "B," which is then di
Leto [7]

Answer: the molarity of the solution in volumetric flask "B' is 0.0100 M

Explanation:

Given that;

the Molarity of stock solution M₁ = 1.25M

The molarity os solution in volumetric flask A (M₂) = M₂

Volume of stock solution pipet out (V₁) = 5.00mL

Volume of solution in volumetric flask A V₂ = 25.00mL

using the dilution formula

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

WE SUBSTITUTE

M₂ =  ( 1.25 × 5.00 ) / 25.00 mL

M₂ = 0.25 M

Now volume of solution pipet out from volumetric flask A V₂ = 2.00 mL

Molarity of solution in volumetric flask B (M₃) = M₃

Volume of solution in volumetric flask B V₃ = 50.00m L

Using dilution formula again

M₂V₂ = M₃V₃

M₃ = M₂V₂ / V₃

WE SUBSTITUTE

M₃ = ( 0.25 × 2.0) / 50.0

M₃ = 0.0100 M

Therefore the molarity of the solution in volumetric flask "B' is 0.0100 M

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3 years ago
HELP PLEASE I dont understand this (7th Grade science)
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Does NH3 dissolve in acetone?
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Acetone will react with ammonia. Acetone will act as an Lewis Acid and ammonia will act as a Lewis Base in this situation. The nitrogen in NH3 is very reactive because of its lone pair of electrons(The nitrogen is delta -ve), so it will attack the carbon cation center of the acetone (which is delta +ve).
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Measurements show that unknown x compound has the following composition:
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The empirical formula of the compound with the percent composition C 18.1%, H 2.27%, Cl 79.8% is C₂H₃Cl₃.

<h3>What is an empirical formula?</h3>

It is the minimum ratio between the elements that form a compound.

  • Step 1: Divide each percentage by the molar mass of the element.

C: 18.1/12.01 = 1.51

H: 2.27/1.01 = 2.25

Cl: 79.8/35.45 = 2.25

  • Step 2: Divide all the numbers by the smallest one.

C; 1.51/1.51 = 1

H: 2.25/1.51 ≈ 1.5

Cl: 2.25/1.51 ≈ 1.5

  • Step 3: Multiply all the numbers by 2 so all of them are whole.

C: 1 × 2 = 2

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Cl: 1.5 × 2 = 3

The empirical formula is C₂H₃Cl₃.

The empirical formula of the compound with the percent composition C 18.1%, H 2.27%, Cl 79.8% is C₂H₃Cl₃.

Learn more about empirical formula here: brainly.com/question/1603500

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