Explanation:
Common ion effect is defined as the effect which occurs on equilibrium when a common ion (an ion which is already present in the solution) is added to a solution. This effect generally decreases the solubility of a solute.
Equilibrium reaction of strontium sulfate and sodium sulfate follows the equation:
According to Le-Chateliers principle: If there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.
In the equilibrium reactions, hypochlorite ion is getting increased on the product side, so the equilibrium will shift in the direction to minimize this effect, which is in the direction of hydrogen hypochlorite.
Thus, the addition hypochlorite ions will shift the equilibrium in the left direction.
The dissociation of hydrogen hypochlorite is suppressed due to the common ion effect.
Answer:
a. -58 millivolts
Explanation:
The given Nernst equation is:
![E_{ion} = 58 millivolts /z \Big[ log_{10} \Big( \dfrac{[ion]_{out}}{[ion]_{in}}\Big) \Big]}](https://tex.z-dn.net/?f=E_%7Bion%7D%20%3D%2058%20millivolts%20%2Fz%20%5CBig%5B%20log_%7B10%7D%20%5CBig%28%20%5Cdfrac%7B%5Bion%5D_%7Bout%7D%7D%7B%5Bion%5D_%7Bin%7D%7D%5CBig%29%20%5CBig%5D%7D)
The equilibrium potential given by the Nernst equation can be determined by using the formula:
![E_{Cl^-} = \dfrac{2.303*R*T}{ZF} \times log \dfrac{[Cl^-]_{out}} {[Cl^-]_{in}}](https://tex.z-dn.net/?f=E_%7BCl%5E-%7D%20%3D%20%5Cdfrac%7B2.303%2AR%2AT%7D%7BZF%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BCl%5E-%5D_%7Bout%7D%7D%20%7B%5BCl%5E-%5D_%7Bin%7D%7D)
where:
gas constant(R) = 8.314 J/K/mol
Temperature (T) = (20+273)K
= 298K
Faraday constant F = 96485 C/mol
Number of electron on Cl = -1
D protons. <span>the identity of an element is determined by the total number of protons present in the nucleus of an atom contained in that partial element.
._.</span>
Answer:
C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
from the question ,
M = 0.250M
V = 3.00 L
M = n / V
n = M * v
n = 0.250M * 3.00 L = 0.75 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
n = 0.75 mol NaOH
m = molecular mass of NaOH = 40 g/mol
n = w / m
w = n * m
w = 0.75 mol * 40 g/mol = 30.0 g
Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .
