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3 years ago

Which sentence about particles in matter is true?

Physics

2 answers:

AlexFokin [52]3 years ago

7 0

Answer:

B. The particles of matter are in constant motion.

Explanation:

The particles of matter are always in constant motion at different speeds when exposed to certain temperatures.

finlep [7]3 years ago

4 0

B. The particles of matter are in constant motion.

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An elevator is moving downward when someone presses the emergency stop button. The elevator comes to rest a short time later. Gi

Oksanka [162]

Answer:

Velocity: +ve, Acceleration: -ve

Explanation:

Here I've considered downward direction as positive direction.

6 0

3 years ago

Read 2 more answers

A horse shoe magnet is placed on a mass balance such that a uniform magnetic field of magnitude B runs between it from North to

BARSIC [14]

Answer:

(a) Measured change in mass (Δm) = BVL/Rg

(b) Total measured mass M' = M - BVL/Rg

Explanation:

Current (I) across is coil is given by the formula;

I = V/R ------------------------1

The magnetic force is given by the formula;

Fb = B*I*L -------------------2

Putting equation 1 into equation 2, we have;

Fb = B*V*L/R -------------------3

Change in mass (Δm) is given as:

Δm = Fb/g -----------------------4

Putting equation 3 into equation 4, we have;

Δm = BVL/Rg

Therefore, change in mass (Δm) = BVL/Rg

2. Since B runs from North to South and current running from East to West, then the magnetic force is directed upward.

Therefore,

Total measure mass M' = M - BVL/Rg

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3 years ago

Four rivers have the same volume of water flow over time but fall from the different heights to power hydroelectric dams. which

sveticcg [70]

Answer:

I thibknits 175

Explanation: It's the furthest

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1 year ago

An electron travels through a particular point in an experimental apparatus with a velocity of 0.949 \times 10^6×10 6 m/s an

Rzqust [24]

Answer:

The magnitude of the acceleration of the electron at this point is $3.94\times10^{14}\ m/s^2$ .

Explanation:

Given that,

Velocity $v= 0.949\times10^{6}\ m/s$

Angle = 61.5°

Magnetic field = 0.01 T

We need to calculate the magnetic force

Using formula of magnetic force

$F=Bev\cos\theta$

Where, B = magnetic field

v = velocity

e = charge of electron

Put the value into the formula

$F=0.01\times1.6\times10^{-19}\times0.949\times10^{6}\cos61.5$

$F=3.59\times10^{-16}\ N$

We need to calculate the acceleration

Using newton's second law

$F= ma$

$a = \dfrac{F}{m}$

Put the value into the formula

$a=\dfrac{3.59\times10^{-16}}{9.1\times10^{-31}}$

$a=3.94\times10^{14}\ m/s^2$

Hence, The magnitude of the acceleration of the electron at this point is $3.94\times10^{14}\ m/s^2$ .

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3 years ago

George is planning an experiment to see how fast different sized cans of soup can roll down a ramp in his kitchen. He will be ro

ddd [48]

If it were me, I would choose D.

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3 years ago