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IRINA_888 [86]
3 years ago
10

Why is the unit of momentum called derived unit​

Physics
1 answer:
Mnenie [13.5K]3 years ago
8 0

Answer:

the SI unit of momentum is :- kg.ms-1

and we know that,

kinetic energy = 1/2 mv2

E=p2/2m

p=(2Em)1/2

so the derived units are (J.kg)1/2

Explanation:

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Mike has a mass of 97 kg. He jumps out of a perfectly good airplane that is 2000 m above the ground. After he falls 1000 m, when
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Answer:

a)  fr = 224.3 N , b)   fr = 224.3 N , c)   v = 198.0  m/s

Explanation:

a) For this exercise let's start by calculating the acceleration in the fall

             v² = v₀² - 2 a (y-y₀)

When it jumps the initial vertical speed is zero

             a = -v² / 2 (y-y₀)

             a = -68 2/2 (1000-2000)

             a = 2,312 m / s²

Let's use the second net law to enter the average friction force

            fr = m a

            fr = 97 2,312

            fr = 224.3 N

b) let's look for acceleration

            v² = v₀² - 2 a y

            a = (v² –v₀²) / 2 (y-y₀)

            a = (4² - 68²) / 2 (0-1000)

            a = 2,304 m / s²

            fr = m a

            fr = 97 2,304

            fr = 223.5 N

c) the speed of the wallet is searched with kinematics

           v² = v₀² - 2 g (y-y₀)

           v = √ (0-2 9.8 (0-2000))

           v = 198.0  m/s

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3 years ago
A manganese atom is pictured below.
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Manganese   has  2 (two) electron  that   would  free  floating   and   able  to  form  a  metallic  bond.
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three letters (JET) are placed in front of a plane mirror the image formed is in what arrangement???​
mario62 [17]

Answer:

TEJ as this is a thing you wont get

3 0
3 years ago
A 15-ft3 tank contains oxygen initially at 14.7 psia and 80°F. A paddle wheel within the tank is rotated until the pressure insi
Nikolay [14]

Explanation:

Equation for energy balance will be as follows.

         \Delta E_{system} = E_{in} - E_{out}

        \Delta U = W_{in} - Q_{out}

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Therefore, we will calculate the final temperature as follows.

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       T_{2} = \frac{20 psia}{14.7}(638 R)

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Now, we will calculate the mass as follows.

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Hence,

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Putting the values into the above equation as follows.

            W_{in} = Q_{out} + mC_{v} (T_{2} - T_{1})

    W_{in} = 20 Btu + 1.031 lbm (\frac{0.160 Btu}{lbm R})(735 - 540)R

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Thus, we can conclude that work done by paddle wheel is 655.2 Btu.

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