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1 year ago

What is the multiplicity of the indicated carbon in an off-resonance decoupled c-13 nmr spectrum?

Chemistry

1 answer:

Nezavi [6.7K]1 year ago

3 0

Tert-butyl alcohol's 13C-NMR spectrum will only display two signals.

(I) Signal at about 31 ppm: This signal is for the more shielded and electron-rich carbon atoms and is upfield. The height of the peak on the y-axis indicates the relative quantity of carbon atoms to other peaks. Since it is three times as tall as the second signal in this instance, it is clear that this peak represents three carbon atoms.

(ii) Signal at about 70 ppm: This signal is directed downfield and pertains to the carbon atom, which is more exposed and has an environment poor in electrons. The height of these peaks is only one carbon higher than the second signal. Furthermore, the exposed environment demonstrates this carbon.

To learn more about the 13C NMR refer here:

brainly.com/question/14686693

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Im in class rn real school help

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Answer:

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3 years ago

How do I write 0.03438 m in scientific notation using 3 digits?

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3.44x10^2
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3 years ago

A 1.00 g sample of a metal X (that is known to form X ions in solution) was added to 127.9 mL of 0.5000 M sulfuric acid. After a

Semenov [28]

<u>Answer:</u> The metal having molar mass equal to 26.95 g/mol is Aluminium

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of NaOH solution = 0.5000 M

Volume of solution = 0.03340 L

Putting values in equation 1, we get:

$0.5000M=\frac{\text{Moles of NaOH}}{0.03340L}\\\\\text{Moles of NaOH}=(0.5000mol/L\times 0.03340L)=0.01670mol$

The chemical equation for the reaction of NaOH and sulfuric acid follows:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+H_2O$

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of sulfuric acid

So, 0.01670 moles of NaOH will react with = $\frac{1}{2}\times 0.01670=0.00835mol$ of sulfuric acid

Excess moles of sulfuric acid = 0.00835 moles

Calculating the moles of sulfuric acid by using equation 1, we get:

Molarity of sulfuric acid solution = 0.5000 M

Volume of solution = 127.9 mL = 0.1279 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.5000M=\frac{\text{Moles of }H_2SO_4}{0.1279L}\\\\\text{Moles of }H_2SO_4=(0.5000mol/L\times 0.1279L)=0.06395mol$

Number of moles of sulfuric acid reacted = 0.06395 - 0.00835 = 0.0556 moles

The chemical equation for the reaction of metal (forming $M^{3+}$ ion) and sulfuric acid follows:

$2X+3H_2SO_4\rightarrow X_2(SO_4)_3+3H_2$

By Stoichiometry of the reaction:

3 moles of sulfuric acid reacts with 2 moles of metal

So, 0.0556 moles of sulfuric acid will react with = $\frac{2}{3}\times 0.0556=0.0371mol$ of metal

To calculate the molar mass of metal for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Mass of metal = 1.00 g

Moles of metal = 0.0371 moles

Putting values in above equation, we get:

$0.0371mol=\frac{1.00g}{\text{Molar mass of metal}}\\\\\text{Molar mass of metal}=\frac{1.00g}{0.0371mol}=26.95g/mol$

Hence, the metal having molar mass equal to 26.95 g/mol is Aluminium

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3 years ago

A solution is classified as a weak base. Which of these could be the pH of the solution?

Pepsi [2]

Explanation:

The pH of a weak base falls somewhere between 7 and 10.

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Mariah needs to identify a cause-and-effect relationship. Which type of investigation should she use?

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Descriptive or Correlational. hope this helps

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3 years ago