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lyudmila [28]
1 year ago
6

What is the multiplicity of the indicated carbon in an off-resonance decoupled c-13 nmr spectrum?

Chemistry
1 answer:
Nezavi [6.7K]1 year ago
3 0

Tert-butyl alcohol's 13C-NMR spectrum will only display two signals.

(I) Signal at about 31 ppm: This signal is for the more shielded and electron-rich carbon atoms and is upfield. The height of the peak on the y-axis indicates the relative quantity of carbon atoms to other peaks. Since it is three times as tall as the second signal in this instance, it is clear that this peak represents three carbon atoms.

(ii) Signal at about 70 ppm: This signal is directed downfield and pertains to the carbon atom, which is more exposed and has an environment poor in electrons. The height of these peaks is only one carbon higher than the second signal. Furthermore, the exposed environment demonstrates this carbon.

To learn more about the 13C NMR refer here:

brainly.com/question/14686693

#SPJ4

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4.2g of cerium reacted with oxygen to form 5.16g of an oxide of cerium. Find
olganol [36]

Answer:

CeO₂

Explanation:

Hello!

In this case, since we are given the mass of both cerium and the cerium oxide, we can first compute the moles of cerium and the moles of oxygen as shown below:

n_{Ce}=4.2gCe*\frac{1molCe}{140.12gCe}=0.03molCe\\

m_O=5.16g-4.2g=0.96gO\\\\n_O=0.96g*\frac{1molO}{16.0gO} =0.06molO

Now, we simply divide each moles by 0.03 as the fewest moles in the formula to obtain the simplest formula (empirical formula) of this oxide:

Ce=\frac{0.03}{0.03}=1\\\\O =\frac{0.06}{0.03}=2

Thus, the formula turns out:

CeO_2

Regards!

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Explanation:

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