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3 years ago

In ancient times, what would the Moon have looked like from the Earth?

Chemistry

2 answers:

ss7ja [257]3 years ago

6 0

The moon would have appeared more vividly and brightly due to the absence of light pollution and smog

Ipatiy [6.2K]3 years ago

6 0

Answer:

It would have looked bigger. Active volcanoes might have been visible on it.

Explanation:

The most widely accepted theory of the Moon formation is Giant Impact hypothesis which states that a giant Mars sized celestial body: Theia hit planet Earth and the material that ejected out of the Earth coalesced and formed Moon. The Moon as observed today is moving away at a rate of around 4 cm per year which means that in ancient times it would have looked much bigger in the sky.

Frozen lava has been seen on the Lunar surface which are called as Maria (dark spots). In ancient times we could have witnessed those active volcanoes.

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CH4 + O2 → CO2 + H2O

Scilla [17]

Answer:

9.8 × 10²⁴ molecules H₂O

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Organic

Naming carbons

Stoichiometry

Analyzing reaction rxn
Using Dimensional Analysis

Explanation:

Step 1: Define

[RxN - Unbalanced] CH₄ + O₂ → CO₂ + H₂O

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 130 g CH₄

Step 2: Identify Conversions

Avogadro's Number

[RxN] 1 mol CH₄ → 2 mol H₂O

[PT] Molar Mass of C: 12.01 g/mol

[PT] Molar Mass of H: 1.01 g/mol

Molar Mass of CH₄: 12.01 + 4(1.01) = 16.05 g/mol

Step 3: Stoichiometry

[DA] Set up conversion: $\displaystyle 130 \ g \ CH_4(\frac{1 \ mol \ CH_4}{16.05 \ g \ CH_4})(\frac{2 \ mol \ H_2O}{1 \ mol \ CH_4})(\frac{6.022 \cdot 10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 9.75526 \cdot 10^{24} \ molecules \ H_2O$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

9.75526 × 10²⁴ molecules H₂O ≈ 9.8 × 10²⁴ molecules H₂O

8 0

3 years ago

When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coeffici

tatuchka [14]

The values of the coefficients would be 4, 5, 4, and 6 respectively.

<h3>Balancing chemical equations</h3>

The equation of the reaction can be represented by the following chemical equation:

ammonia (g) + oxygen (g) ---> nitrogen monoxide (g) + water (g)

$4NH_3(g)$ + $5O_2(g)$ ---> $4NO(g)$ + $6H_2O(g)$

Thus, the coefficient of ammonia will be 4, that of oxygen will be 5, that of nitrogen monoxide will be 4, and that of water will be 6.

More on balancing chemical equations can be found here: brainly.com/question/15052184

#SPJ1

5 0

2 years ago

What is the correct name for the chemical formula N408?

Alexandra [31]

Answer:

molar mass (molar weight)

Explanation:

7 0

3 years ago

Read 2 more answers

Calculate the volume of hydrogen if you have 12.1 moles of Hydrogen.

vodomira [7]

To Find :

The volume of 12.1 moles hydrogen at STP.

Solution :

We know at STP, 1 mole of gas any gas occupy a volume of 22.4 L.

Let, volume of 12.1 moles of hydrogen is x.

So, x = 22.4 × 12.1 L

x = 271.04 L

Therefore, the volume of hydrogen gas at STP is 271.04 L.

8 0

2 years ago

If a 12-volt battery produces a current of 20 amps, what is the resistance?

mixas84 [53]

Answer:

0.6 Ω

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Current (I) = 20 A

Resistance (R) =?

From Ohm's law,

V = IR

Where:

V => is the voltage

I => is the current

R => R is the resistance

With the above formula, we can obtain the resistance as follow:

Voltage (V) = 12 V

Current (I) = 20 A

Resistance (R) =?

V = IR

12 = 20 × R

Divide both side by 20

R = 12 / 20

R = 0.6 Ω

Thus the resistance is 0.6 Ω

4 0

3 years ago