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Oduvanchick [21]
3 years ago
14

In ancient times, what would the Moon have looked like from the Earth?

Chemistry
2 answers:
ss7ja [257]3 years ago
6 0
The moon would have appeared more vividly and brightly due to the absence of light pollution and smog
Ipatiy [6.2K]3 years ago
6 0

Answer:

It would have looked bigger. Active volcanoes might have been visible on it.

Explanation:

The most widely accepted theory of the Moon formation is Giant Impact hypothesis which states that a giant Mars sized celestial body: Theia hit planet Earth and the material that ejected out of the Earth coalesced and formed Moon. The Moon as observed today is moving away at a rate of around 4 cm per year which means that in ancient times it would have looked much bigger in the sky.

Frozen lava has been seen on the Lunar surface which are called as Maria (dark spots). In ancient times we could have witnessed those active volcanoes.

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PLZ HELP PLZ PLZ ILL MARK AS BRAINLIESTT!!!!
LuckyWell [14K]

Q.1-

Given,

mass - 10grams

volume - 24 cm³

density = mass/volume

density = 10/24

density = 0.416 g/cm³

Q.2-

Given,

mass - 700grams

volume - 1100cm³

density = mass/volume

density = 700/1100

density = 0.6363 g/cm³

5 0
3 years ago
What assumptions do we make in order to use the Henderson-Hasselbalch equation? a. Both the weak acid and its conjugate base are
zepelin [54]

Answer:

The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.

Explanation:

The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.

Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i

Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.

It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.

7 0
3 years ago
4.85 x 10^-4 tons to cups
fiasKO [112]

Answer:

2.08753919851 cups

0.464942810185139 cups

2.08753919851 cups

Explanation:

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7 0
3 years ago
Charle's Law
Setler [38]

Convert temperature to Kelvin

  • 225°C=498K
  • 127°C=400K

Convert vol to L

  • 400mL=0.4L

Apply Charles law

  • V1T_2=V2T_1
  • 0.4(400)=498V_2
  • 160=498V_2
  • V_2=0.32L=320mL
8 0
2 years ago
Read 2 more answers
Which is a characteristic of mixtures
barxatty [35]
They are three types of mixtures:
-solutions : they are homogeneous mixtures of 2 or more sub. in a single phase.
-suspensions: if the particles in a solvent are so large that they settle out unless constantly tired, the mixture is called a suspension.
-colloids: particles that are intermediate in size between those of solutions and suspensions form mixtures called colloids.

:)
5 0
3 years ago
Read 2 more answers
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