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Bess [88]
4 years ago
15

Write the mechanism for the two steps of the hydroboration/oxidation reaction of indene

Chemistry
1 answer:
iVinArrow [24]4 years ago
5 0
It's difficult to write it down, but I'll attach you a good example of hydroboration of indene. I hope you'll find it helpful.

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We add 1.4 moles to 700 mL of water. What is the molarity
Nastasia [14]

Answer:

Molarity= 2M

Explanation:

n=1.4, V= 700ml= 0.7dm3

n= CV

1.4= C×0.7

C= 1.4/0.7= 2M

8 0
4 years ago
When K2Cr2O7 is cooled from 80oC to 20oC, how much solute will precipitate out of the solution?
Setler [38]

Answer:

The amswer to the question is A

3 0
3 years ago
Use the drop-down menus to seled the correct responses to each question about ocean zones
chubhunter [2.5K]

Answer:

Intertidal zone

Neritic zone

Open-ocean zone

Note: the correct questions are found below;

In which zone do you find marshes and mangrove forests?

In which zone are plankton plentiful, providing plenty of food for the fish that live there?

In which zone would you find very little plant or animal life compared to other zones?

Explanation:

The intertidal zone, sometimes called the littoral zone, is the area of the marine shoreline that is exposed to air at low tide, and covered with seawater when the tide is high. Intertidal zonation refers to the tendency of plants and animals to form distinct communities between the high and low tide lines. Some microclimates in the littoral zone are moderated by local features and larger plants such as mangroves.

The neritic zone is the region of shallow water (200 meters depth) above the continental shelf where light penetrates to the sea floor.

Due to the abundant supply of sunlight and nutrients such as plankton in this zone, it is the most productive ocean zone supporting the vast majority of marine life.

The open oceans or pelagic ecosystems are the areas away from the coastal boundaries and above the seabed. It encompasses the entire water column and lies beyond the edge of the continental shelf. It extends from the tropics to the polar regions and from the sea surface to the abyssal depths.

7 0
4 years ago
Read 2 more answers
What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 40.88 mL of a 0.3842 M solution o
tatyana61 [14]

Explanation:

As molarity is the number of moles placed in a liter of solution. Therefore, no. of mole = Molarity × volume of solution in liter

Hence, moles of Cu(NO_{3})_{2} will be calculated as follows.

No. of mole of Cu(NO_{3})_{2} = 0.3842 M \times 0.04388 L = 0.0168 mole

According to the given reaction, 2 mole of Cu(NO_{3})_{2} react with 4 mole of KI.

Therefore, for 0.0168 mole amount of Cu(NO_{3})_{2} required will be as follows.

Cu(NO_{3})_{2} = 0.0168 \times \frac{4}{2}

                       = 0.0337 mole of KI

Hence, volume of KI required will be calculated as follows.

               Volume = \frac{\text{no. of moles}}{Molarity}

    Volume of KI = \frac{0.0337}{0.2089}

                           = 0.1614 liter

                            = 161.4 ml            (as 1 L = 1000 mL)

Thus, we can conclude that 161.4 ml  volume of a 0.2089 M KI is required for the given situation.

5 0
4 years ago
Pls help me with this question!
Liono4ka [1.6K]
C and d is correct one
7 0
3 years ago
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