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Ket [755]
4 years ago
11

Ethylene gas and steam at 320°c and atmospheric pressure are fed to a reaction process as an equimolar mixture. the process prod

uces ethanol by the reaction: c2h4(g) + h2o(g) → c2h5oh(l)c2h4(g) + h2o(g) → c2h5oh(l) the liquid ethanol exits the process at 25°c. what is the heat transfer associated with this overall process per mole of ethanol produced?
Chemistry
1 answer:
Reil [10]4 years ago
4 0
The heat transfer formula is;
Q = m * c * Δ T >>>> (1)
where, Q is the heat transfer
m = mass  (gram)
c = the specific heat capacity (J/g)
Δ T = change in temperature
∵ we have one mole of Ethanol
∴ the weight of ethanol equals its molecular weight = (2*12)+(6*1)+(16) = 46 g
we will assume that the specific heat capacity of ethanol is 2.46 J/g (from google) 
ΔT = 25 - 320 = - 295 C
By substitution in (1)
∴ Q = 2.46 * 46 * (-295) = - 33382.2 J
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How many grams of aluminum sulfate form when 3.90 grams of aluminum is placed in 13.65 grams of sulfuric acid?
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Answer:

Mass = 17.12 g

Explanation:

Given data:

Mass of Al = 3.90 g

Mass of H₂SO₄ = 13.65

Mass of aluminium sulfate = ?

Solution:

Chemical equation:

3H₂SO₄ + 2Al   →  Al₂(SO₄)₃ + 3H₂

Now we will calculate the number of moles of each reactant.

Moles of H₂SO₄:

Number of moles = mass/ molar mass

Number of moles = 13.65 g/ 98.079 g/mol

Number of moles = 0.14 mol

Moles of Al:

Number of moles = mass/ molar mass

Number of moles = 3.90 g/ 27 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of aluminium sulfate with sulfuric acid and aluminium.

                           H₂SO₄       :         Al₂(SO₄)₃

                               3            :              1

                           0.14            :          1/3×0.14 = 0.05

                              Al            :           Al₂(SO₄)₃

                               2            :             1

                            0.14           :        1/2×0.14 = 0.07

The number of moles of aluminium sulfate produced by sulfuric acid are less so it will limiting reactant and limit the amount of aluminium sulfate.

Mass of aluminium sulfate:

Mass = number of moles × molar mass

Mass = 0.05 mol × 342.15 g/mol

Mass = 17.12 g

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Answer:

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An empty beaker weighs 25.91 g. When completely filled with water, the beaker and its contents have a total mass of 333.85 g. Wh
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Answer:

The beaker holds 307.94  mL

Explanation:

As we know that the volume that beaker hold is the volume of water that occupied by it.

For this first we have to find mass of the water in the beaker

This can be calculated by the subtraction of beaker's weight from the weight of beaker and water.

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Weight of water = 333.85 - 25.91 = 307.94 g

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We have

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      Volume = 307.94  mL

The beaker holds 307.94  mL

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