1. 9.36 moles S
2. 0.213 moles Al
<h3>Further explanation</h3>
Given
Reaction
2Al+3S⇒Al₂S₃
Required
moles of S
moles of Al
Solution
The reaction coefficient in a chemical equation shows the mole ratio of the compounds involved in the reaction (reactants or products)
From equation, mol ratio of Al₂S₃ : S = 1 : 3, so mol S :
= 3/1 x mol Al₂S₃
= 3/1 x 3.12
= 9.36 moles S
From equation, mol ratio of Al : S = 2 : 3, so mol Al :
= 2/3 x mol S
= 2/3 x 0.32
= 0.213 moles Al
Answer:
32.83 grams of NH₄F can be formed from 34.6 grams of CaF₂
Explanation:
The balanced reaction is:
CaF₂ + (NH₄)₂O ⇒ 2 NH₄F + CaO
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following quantities participate in the reaction:
- CaF₂: 1 mole
- (NH₄)₂O: 1 mole
- NH₄F: 2 mole
- CaO: 1 mole
Being the molar mass of the compounds:
- CaF₂: 78 g/mole
- (NH₄)₂O: 52 g/mole
- NH₄F: 37 g/mole
- CaO: 56 g/mole
Then by stoichiometry, the following amounts of mass participate in the reaction:
- CaF₂: 1 mole* 78 g/mole= 78 g
- (NH₄)₂O: 1 mole* 52 g/mole= 52 g
- NH₄F: 2 mole* 37 g/mole= 74 g
- CaO: 1 mole* 56 g/mole= 56 g
You can apply the following rule of three: if 78 grams of CaF₂ form 74 grams of NH₄F by stoichiometry, 34.6 grams of CaF₂ will form how much mass of NH₄F?

mass of NH₄F= 32.83 grams
<u><em>32.83 grams of NH₄F can be formed from 34.6 grams of CaF₂</em></u>
<u><em></em></u>
The following is the arrangement of the given molecules in decreasing order of mass: 
<u>Solution:</u>
First inorder to arrange the elements in descending order of their mass we have to calculate the molecular mass of each element. The calculation is as follows:
<u>Mass of C6H14:</u>


<em>Mass of C6H14 is 86.172</em>
<u>Mass of NO2:</u>


<em>Mass of NO2 is 46.0055</em>
<u>Mass of Fe2O3:</u>


<em>Mass of Fe2O3 is 159.6882</em>
<u>Mass of CaCO:</u>


<em>Mass of CaCO will be 68.0874</em>
So, the order will be
which is 
Answer:
60.7 mole
Explanation:
for every 4 moles of iron 3 moles of oxygen is used.
So, moles of oxygen =
= 60.675
find mol of N2 present using gas law equation
PV = nRT
P = pressure = 688/760 = 0.905 atm.
V = 100mL = 0.1L
n = ???
R = 0.082057
T = 565+273 = 838
Substitute:
0.905*0.1 = n*0.082057*838
n = 0.0905 / 68.76
n = 0.00132 mol N2
Molar mass N2 = 28 g/mol
0.00132 mol = 0.00132*28 = 0.037g N2 gas