Answer:
W=0.94J
Explanation:
Electrostatic potential energy is the energy that results from the position of a charge in an electric field. Therefore, the work done to move a charge from point 1 to point 2 will be the change in electrostatic potential energy between point 1 and point 2.
This energy is given by:
So, the work done to move the chargue is:
The work is positive since the potential energy in 1 is greater than 2.
Here is the missing part of the question
To Determine the heat transfer, in kJ if the final temperature in the tank is 110 deg C
Answer:
Explanation:
The image attached below shows the process on T - v diagram
<u>At State 1:</u>
The first step is to find the vapor pressure
= 0.5 × 232 kPa
= 116 kPa
The initial specific volume of the vapor is:
<u>At State 1:</u>
The next step is to determine the mass of water vapor pressure.
= 1.578 kg
Using the ideal gas equation to estimate the mass of the dry air
For the specific volume , we get the identical value of saturation temperature
Thus, at , condensation needs to begin.
However, since the exit temperature tends to be higher than the saturation temperature, then there will be an absence of condensation during the process.
Heat can now be determined by using the formula
Q = ΔU + W
Recall that: For a rigid tank, W = 0
Q = ΔU + 0
Q = ΔU
Q = U₂ - U₁
Also, the mass will remain constant given that there will not be any condensation during the process from state 1 and state 2.
<u>At State 1;</u>
The internal energy is calculated as:
At = 125° C, we obtain the specific internal energy of air
SO;
At = 125° C, we obtain the specific internal energy of water vapor
= 6.216 × 284.714 + 1.578 × 2534.5
= 5768.716 kJ
<u>At State 2:</u>
The internal energy is calculated as:
At temperature 110° C, we obtain the specific internal energy of air
SO;
At temperature 110° C, we obtain the specific internal energy of water vapor
= 6.216 × 273.862 + 1.578 × 2517.9
= 5675.57 kJ
Finally, the heat transfer during the process is
Q = U₂ - U₁
Q = (5675.57 - 5768.716 ) kJ
Q = -93.146 kJ
with the negative sign, this indicates that heat is lost from the system.
Explanation:
Since, the rod is present in vertical position and the spring is unrestrained.
So, initial potential energy stored in the spring is = 0
And, initial potential gravitational potential energy of the rod is .
It is given that,
mass of the bar = 0.795 kg
g = 9.8
L = length of the rod = 0.2 m
Initial total energy T =
Now, when the rod is in horizontal position then final total energy will be as follows.
T =
where, I = moment of inertia of the rod about the end =
Also,
where, = speed of the tip of the rod
x = spring extension
The initial unstrained length is = 0.1 m
Therefore, final length will be calculated as follows.
x' = m
Then, x =
x = m - 0.1 m
= 0.1236 m
k = 25 N/m
So, according to the law of conservation of energy
Putting the given values into the above formula as follows.
v = 2.079 m/s
Thus, we can conclude that tangential speed with which end A strikes the horizontal surface is 2.079 m/s.