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4 years ago

What causes deep ocean currents?

Physics

2 answers:

galben [10]4 years ago

4 0

Ocean currents are caused by density differences in the water and move water masses through the deep ocean

Thepotemich [5.8K]4 years ago

4 0

Currents may also be generated by density differences in water masses caused by temperature and salinity variations. These currents move water masses through the deep ocean—taking nutrients, oxygen, and heat with them.

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In every atom, one or more positive charges are positioned ______.

faust18 [17]

In a dense core called the nucleus

Silver

6 0

3 years ago

A sample of gas has a volume of 25L at a pressure of 200 kPa and a temperature of 25°C. What would be the volume if the pressure

frozen [14]

Answer:

18 L

Explanation:

Use ideal gas law:

PV = nRT

Find initial number of moles, but first convert to units that match the gas constant units.

(200,000 Pa) (0.025 m³) = n (8.314 Pa m³ / mol / K) (25 + 273.15 K)

n = 2.017 mol

At the new pressure and temperature:

(250,000 Pa) V = (2.017 mol) (8.314 Pa m³ / mol / K) (0 + 273.15 K)

V = 0.018 m³

V = 18 L

3 0

4 years ago

Carole owns a two story house with a heating and cooling unit on each floor. In the winter she mostly uses the downstairs unit b

alisha [4.7K]

A. Expands, Rises, Convection

3 0

3 years ago

Read 2 more answers

When riding a 10-speed bicycle up a hill, a cyclist shifts the chain to a larger-diameter gear attached to the back wheel. Why i

dimaraw [331]

To solve this problem we will use the concepts of the moment of rotational inertia, angular acceleration and the expression of angular velocity.

The rotational inertia is expressed as follows:

$I = \sum mr^2$

Here,

m = Mass of the object

r = Distance from the rotational axis

The rotational acceleration in terms of translational acceleration is

$\alpha = \frac{a}{R}$

Here,

a = Acceleration

R = Radius of the circular path of the object

The expression for the rotational speed of the object is

$\omega = \frac{\Delta \theta}{\Delta t}$

Here,

$\Delta \theta$ is the angular displacement of the object

The explanation by which when climbing a mountain uphill is changed to a larger pinion, is because it produces a greater torque but it is necessary to make more pedaling to be able to travel the same distance. Basically every turn results in less rotations of the rear wheel. Said energy that was previously used to move the rotation of the wheel is now distributed in more turns of the pedal. Therefore option a and c are correct.

This would indicate that the correct option is D.

8 0

4 years ago

A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity and displ

Anestetic [448]

Answer:

a. -39.2 m/s; -78.4 m

b. -31.2 m/s; -46.4 m

c. -47.2 m/s; -110.4 m

Explanation:

We are given/can infer these variables:

t = 4.0 s
a = -9.8 m/s²
v_0 = 0 m/s

We want to find the displacement and the final velocity of the rock.

Δx = ?
v = ?

We can use this equation to find the final velocity:

v = v_0 + at

Plug in the known variables into this equation.

v = 0 + (-9.8)(4.0)
v = -9.8 * 4.0
v = -39.2 m/s

The final velocity of the rock is -39.2 m/s.

Now we can use this equation to find the displacement of the rock:

Δx = v_0 t + 1/2at²

Plug in the known variables into this equation.

Δx = 0 * 4.0 + 1/2(-9.8)(4.0)²
Δx = 1/2(-9.8)(4.0)²
Δx = -4.9 * 16
Δx = -78.4 m

The displacement of the rock is -78.4 m.

We are given/can infer these variables:

v_0 = 8.0 m/s
a = -9.8 m/s²
t = 4.0 s

We can use this equation to find the final velocity:

v = v_0 + at

Plug in the known variables into this equation.

v = 8.0 + (-9.8)(4.0)
v = 8.0 + -39.2
v = -31.2 m/s

The final velocity of the rock is -31.2 m/s.

We can use this equation to find the displacement:

Δx = v_0 t + 1/2at²

Plug in known variables:

Δx = 8.0(4.0) + 1/2(-9.8)(4.0)²
Δx = 32 - 4.9(16)
Δx = -46.4 m

The displacement of the rock is -46.4 m.

We are given/can infer these variables:

v_0 = -8.0 m/s
a = -9.8 m/s²
t = 4.0 s

We can use this equation to find the final velocity:

v = v_0 + at

Plug in the known variables into this equation.

v = -8.0 + (-9.8)(4.0)
v = -8.0 - 39.2
v = -47.2 m/s

The final velocity of the rock is -47.2 m/s.

We can use this equation to find the displacement:

Δx = v_0 t + 1/2at²

Plug in known variables:

Δx = -8.0(4.0) + 1/2(-9.8)(4.0)²
Δx = -32 - 4.9(16)
Δx = -110.4 m

The displacement of the rock is -110.4 m.

8 0

3 years ago