1) First of all, let's find the resistance of the wire by using Ohm's law:
![V=IR](https://tex.z-dn.net/?f=V%3DIR)
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
![R= \frac{V}{I}= \frac{5.70 V}{17.6 A}=0.32 \Omega](https://tex.z-dn.net/?f=R%3D%20%5Cfrac%7BV%7D%7BI%7D%3D%20%5Cfrac%7B5.70%20V%7D%7B17.6%20A%7D%3D0.32%20%5COmega%20%20)
2) Now that we have the value of the resistance, we can find the resistivity of the wire
![\rho](https://tex.z-dn.net/?f=%5Crho)
by using the following relationship:
![\rho = \frac{RA}{L}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%20%5Cfrac%7BRA%7D%7BL%7D%20)
Where A is the cross-sectional area of the wire and L its length.
We already have its length
![L=2.90 m](https://tex.z-dn.net/?f=L%3D2.90%20m)
, while we need to calculate the area A starting from the radius:
![A=\pi r^2 = \pi (0.654\cdot 10^{-3}m)^2=1.34 \cdot 10^{-6}m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%20%3D%20%5Cpi%20%280.654%5Ccdot%2010%5E%7B-3%7Dm%29%5E2%3D1.34%20%5Ccdot%2010%5E%7B-6%7Dm%5E2)
And now we can find the resistivity:
The car experiences more because the suv has more mass
Answer:
A ruler in centimeters and/or inches.
Explanation:
This is the most convenient option to measure a soda can.
They hit positive charges in the gold atoms.
As alpha particles are positively charged particles, they will experience repulsion force as soon as they approach positive charges in the center of the atom (in the nucleus).
Also remember that back at Rutherford time, they did not have the right visualization of the atom, they had a model of it like if it was a budding of positive charges and the negative charges are put into them. So this experiment gave a really better and more reliable imagination of the atom structure.
Hope this helps.