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3 years ago

Which term names the area between Mars and Jupiter?

Physics

2 answers:

disa [49]3 years ago

8 0

asteroid belt!! Is in between Jupiter and mars

xeze [42]3 years ago

7 0

Asteroid belt is the area between Mars and Jupiter.

Answer: Option C

<u>Explanation:</u>

The region between orbit of Mars and the orbit of Jupiter is called as asteroid belt. The asteroid belt consists of several number of asteroids inside the belt which are considered to be the left overs of the solar system.

Rock gas boundary usually consists of rocks and gas inside the region which is not applicable to define the space between mars and Jupiter.

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A boy starting from rest, slides down a snowy hill on a sled. He travels 174.19 m to the bottom of the hill. He accelerates

AfilCa [17]

Answer:

11.6 s

Explanation:

We can use equation of motiom to solve this

$s = ut + \frac{1}{2} a {t}^{2 } \\ 174.19 = (0)t + \frac{1}{2} (2.61){t}^{2 } \\ t = 11.6s$

4 0

3 years ago

K2O Use IUPAC nomenclature rules to properly identify this compound. A) potassium oxide B) dipotassium oxide C) potassium (I) ox

Lostsunrise [7]

This molecule is formed between a not very electronegative metal and a very electronegative nonmetal which means it should be an ionic compound which would mean that it would have the name of potassium oxide.

look up the naming rules for ionic compounds. I would explain it here but I don't know how to explain naming the anion part of the molecule other than it ends in ide since it is a monoatomic anion which is why oxide is in the name instead of oxygen.

I hope this helps. Let me know if anything is unclear or needs more explanation.

6 0

3 years ago

Read 2 more answers

Just think about this.

diamong [38]

This ain’t the place, bud. If you have a QUESTION, then you can post it here.

8 0

3 years ago

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What is the magnification of a virtual image if the image is 10.0 cm from a lens and the object is 30 cm from the lens

7nadin3 [17]

Answer:

The magnification of a virtual image is -0.33

Explanation:

We can calculate the magnification as the ratio of height of the image to the height of the object. It can be also stated as the ratio of size of the image obtained to the original size of the object. Also this ratio can be equated to the ratio of image distance to object distance. So magnification can be termed as ratio of image distance to object distance. As in the present case, the image distance or the distance of the formation of image from the lens is 10 cm and the distance of object from the lens or the object distance is 30 cm. Then, $Magnification =-\frac{Image distance}{Object distance}=-\frac{10}{30}=-0.33$ .

So, the image will be diminished to 0.33 times the original size as the magnification of the virtual image is obtained as -0.33.

5 0

3 years ago

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Put the balloon near (BUT NOT TOUCHING) the wall. Leave about as much space as the width of your pinky finger between the balloo

natka813 [3]

Answer:

Move towards the wall.

Explanation:

When the balloon is kept near to the wall not touching the wall, there is a force of electrostatic attraction so that the balloon moves towards the wall and stick to it.

As there is some charge on the balloon and the wall is uncharged so the force is there due to which the balloon moves towards the wall.

3 0

3 years ago