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Gennadij [26K]
3 years ago
9

Work is being done when

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
B. an object is moving after you apply force to it
You might be interested in
what voltage would produce a current of 100A through an aluminum wire that has a resistance of 3.44x10^-4 ohm?
Serga [27]
Voltage = Current x Resistance 
<span>Voltage(?) = 100 x 1.98x10^-4 ohms </span>

<span>Voltage = Current x Resistance </span>
<span>Voltage(?) = 250 x 2.09x10^-4 ohms </span>

<span>Voltage = Current x Resistance </span>
<span>Voltage(?) = 100 x 3.44x10^-4 ohms</span>
7 0
3 years ago
While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th
Zepler [3.9K]

Answer:

v=3.47m/s

Explanation:

The speed is by definition the distance traveled divided over the time it takes to travel that distance. In this case, this distance is the circumference of the wheel, so we have:

v=\frac{C}{t}=\frac{2\pi r}{t}

where we have written the circumference in terms of its radius.

For our values we then obtain the value:

v=\frac{2\pi r}{t}=\frac{2\pi (16m)}{(29s)}=3.47m/s

5 0
3 years ago
Find the position of the center of mass of the system of the sun and Jupiter? (Since Jupiter is more massive than the rest of th
8090 [49]

Answer:

r_{cm} = 0.074 m from the position of the center of the Sun

Explanation:

As we know that mass of Sun and Jupiter is given as

M_s = 1.98 \times 10^{30} kg

M_j = 1.89 \times 10^{27} kg

distance between Sun and Jupiter is given as

r = 7.78 \times 10^{11} m

now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them

so we will have

r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}

r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}

r_{cm} = 0.074 m from the position of the center of the Sun

3 0
3 years ago
A flashlight contains a battery of two cells in series, with a bulb of resistance 12 Ohms. The internal resistance of each cell
Elina [12.6K]

Answer:

1.5024

Explanation:

Draw a diagram. Put the two cells in series. Now draw 3 resistors. Two of them equal 0.26 ohms each. The third one is the lightbulb which is 12 ohms.

R = 0.26 + 0.26 + 12 = 12.52

The bulb has a voltage of 2.88 volts across it. You can get the current from that.

i = E / R

i = 2.88 / 12 =

i = 0.24 amps.

Now you can get the voltage drop across the two cells.

E = ?

R = 0.26

i = 0.24 amps

E = 0.26 * 0.24

E = 0. 0624

Finally divide the 2.88 by 2 to get 1.44

Each cell has an emf of 1.44 + 0.0624 = 1.5024

4 0
2 years ago
What do you think that astronomers mean when they use the term observable universe?
iren2701 [21]
The observable universe consists of galaxies and other matter that can, principally, be seen from Earth because the light signals have had time to reach us. Not everything in the sky is the way it is when we see it, because of the distance the light travels to reach us. 

Hope this helps :)
6 0
3 years ago
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