1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dolphi86 [110]
3 years ago
15

An acorn falls from a branch located 9.8 m above the ground. After 1 s of falling, the acorn's velocity will be 9.8 m/s downward

. Why hasn't the acorn hit the ground?
Physics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

The acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

Explanation:

given information:

h =9.8

t =1 s

g = 9.8

the average speed

v = 1/2 gt²

   = 1/2 (9.8) (1)²

   = 4.8 m/s

the distance in 1s

h = v t

   = 4.8 (1)

   = 4.8 m

the acorn hasn't hit the ground because it only falsl half of the branch distance from the ground

   =

You might be interested in
a man pulls a box with a force of 90.00 N directed along the handle which makes angle of 45 degrees with the ground. Find the ho
IrinaK [193]

Answer:

both are 45√2N

Explanation:

90 sin45°=90 cos45°=45√2N

3 0
3 years ago
A 600 g model rocket is on a cart that is rolling to the right at a speed of 4.0 m/s. The rocket engine, when it is fired, exert
murzikaleks [220]

Answer:

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

Explanation:

Step 1: Data given

mass of the rocket = 600 grams

speed = 4.0 m/s

Step 2: Calculate weight

Fw = mg

with Fw = the weight (in Newton)

with m = the mass (in kg)

with g = the acceleration due to gravity (9.81 m/s²).

Fw = (0.600 kg)(9.81 m/s²)  = 5.886 N

Step 3: Calculate force available to provide acceleration

The rocket engine, when it is fired, exerts a 8.0 AND vertical thrust on the rocket.

5.886 N of that force will be used to counter the rocket's weight, leaving 2.114 N of force available to provide acceleration.  

Step 4: Calculate the rocket's upward acceleration:

Fnet = m*a

With Fnet = the net force (the force that remains after the rocket's weight is compensated)

with a = the rocket's acceleration (in m/s²)

2.114 N = (0.600 kg)*a

a = 3.52 m/s²  = the rocket's upward acceleration

Step 5: Calculate how long it will take to rise 20 meters into the air.

Δy = v0*t + 1/2 at²

with v0 = 0m/s

Δy = 1/2 at²

20 m = 1/2(3.52)t²

20 m = (1.76 m/s²)t²

11.36 = t²

t = 3.37 s

This means the rocket will take 3.37 seconds to reach the hoop.  It should be launched when the cart is 3.37 seconds away from being directly beneath the hoop.  

Step 6: Calculate the distance

v = Δx / t

4.0 m/s = Δx / 3.37 s

Δx = 13.48 m

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

8 0
3 years ago
A brave child decides to grab onto an already spinning merry‑go‑round. The child is initially at rest and has a mass of 34.5 kg.
rodikova [14]

Answer:

the moment of inertia of the merry go round is 38.04 kg.m²

Explanation:

We are given;

Initial angular velocity; ω_1 = 37 rpm

Final angular velocity; ω_2 = 19 rpm

mass of child; m = 15.5 kg

distance from the centre; r = 1.55 m

Now, let the moment of inertia of the merry go round be I.

Using the principle of conservation of angular momentum, we have;

I_1 = I_2

Thus,

Iω_1 = I'ω_2

where I' is the moment of inertia of the merry go round and child which is given as I' = mr²

Thus,

I x 37 = ( I + mr²)19

37I = ( I + (15.5 x 1.55²))19

37I = 19I + 684.7125

37I - 19 I = 684.7125

18I = 684.7125

I = 684.7125/18

I = 38.04 kg.m²

Thus, the moment of inertia of the merry go round is 38.04 kg.m²

7 0
4 years ago
Read 2 more answers
A motorcycle is capable of accelerating at 1.5 m/s2. Starting from rest, how far can it travel in 0.5 seconds?
Helen [10]
Answer:
Here,
Initial velocity(u)=0 m/s
acceleration(a)=1.5m/s
time(t)=0.5s
Now,
distance covered(s)=ut+(1/2)at^2
                            =0*0.5+(1/2)*1.5*0.5*0.5
                             =0+(1/2)*0.375
                             =0+0.1875
                             =0.1875(nearly 0.19)
Hence,0.19 is correct answer.
                                       

6 0
4 years ago
The Sun delivers an average power of 1150 W/m2 to the top of the Earth’s atmosphere. The permeability of free space is 4π × 10−7
My name is Ann [436]

Answer:

E=930.84 N/C

Explanation:

Given that

I = 1150 W/m²

μ = 4Π x 10⁻⁷

C = 2.999 x 10⁸ m/s

E= C B

C=speed of light

B=Magnetic filed  ,E=Electric filed

Power  P = I A

A=Area=4πr²  ,I=Intensity

I=\dfrac{CB^2}{2\mu_0}

I=\dfrac{CE^2}{2\mu_0 C^2}

E=\sqrt{{2I\mu_0 C}}

E=\sqrt{{2\times 1150\times 4\pi \times 10^{-7}(2.99792\times 10^8)}}

E=930.84 N/C

Therefore answer is 930.84 N/C

4 0
4 years ago
Other questions:
  • Beet juice is added to a unknown solution and changes color from red to purple. Curry powder, added to the same solution, turns
    15·2 answers
  • a 10-N force is exerted on a box, moving it 20 m in the same direction. What is the magnitude of work done on the box?
    6·1 answer
  • A sample of 5.6 L of a gas is at a pressure of 1.5 atm. If the volume of the gas is compressed to 4.8 L, what will the new press
    9·2 answers
  • Where does the water come from?
    9·1 answer
  • A quarter circle of radius a is centered about the origin in the first quadrant and carries a uniform charge of −Q. Find the x-
    14·1 answer
  • True or false questions for work and power.​
    8·1 answer
  • A plane starts from rest accelerates to 40 m/s in 10 seconds. How far did the plane travel during this time?
    12·1 answer
  • Would lifting a 1 kg block 1 meter off the ground be work? Yes or No
    15·1 answer
  • Which of the following is a product in the process of photosynthesis?
    5·1 answer
  • You are driving on a rural road and see a person on the shoulder ahead, riding or leading an
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!