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a_sh-v [17]
3 years ago
14

What is the ratio of the sun’s gravitational pull on Mercury to the sun’s gravitational pull on the earth?

Physics
1 answer:
Marta_Voda [28]3 years ago
4 0

Answer:

The answer is \frac{F_{Sun-Mercury} }{F_{Sun-Earth} } =0,3709. Let's learn why.

Explanation:

Newton's law of universal gravitation says;

F_{g} =G.\frac{m_{1}.m_{2}}{r^{2}}

Here G is a universal gravitational <u>constant</u> and is measured experimentally.

Sun's gravitational pull on mercury is:

F_{Sun-Mercury} =G.\frac{m_{sun}.3,30.10^{23}}{(5,79.10^{10})^{2} }

Therefore F_{Sun-Mercury} = Gm_{sun} 98,4366

Sun's gravitational pull on Earth is:

F_{Sun-Earth} =G.\frac{m_{sun} 5,97.10^{24} }{(1,50.10^{11}) ^{2}}

Therefore F_{Sun-Earth} =Gm_{sun} 265,33

As a result;

\frac{F_{Sun-Mercury}}{F_{Sun-Earth} }=\frac{Gm_{sun}98,4366}{Gm_{sun}265,33 } =0,3709

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Sauron [17]

The density of the nickel was greater than that of the quarter and penny, thus, the results supports the hypothesis.

<h3>What is density of substance?</h3>

The density of a substance is a measure of how tightly-packed the particles of the substance are.

Density is calculated as the ratio of the mass of the substance and the volume of the substance.

  • Density = mass/volume

The hypothesis of the lab to compare the densities of a penny, a nickel, and a quarter is:

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The average mass and the average volume of a penny, a nickel, and a quarter are then used to determine the density of each coin.

Based on obtained results, it would be found that the density of the nickel was greater than that of the quarter and penny. Therefore, the results supports the hypothesis.

In conclusion, the density of a substance depends on the mass and the volume.

Learn more about density at: brainly.com/question/1354972

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7 0
1 year ago
Light is shone on a diffraction grating
Pani-rosa [81]

Answer:

    λ = 482.05 nm

Explanation:

The diffraction phenomenon and the diffraction grating is described by the expression

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where d is the distance between two consecutive slits, λ the wavelength and m an integer representing the order of diffraction

in this case they indicate the distance between slits, the angle and the order of diffraction

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let's calculate

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Let's reduce to nm

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3 years ago
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Answer:

Explanation:

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