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3 years ago

Doubling an objects speed will have what effect on its potential energy due to gravity

Physics

1 answer:

prohojiy [21]3 years ago

4 0

An object's gravitational potential energy is

(mass) x (gravity) x (height above ground) .

I don't see the object's speed anywhere in that formula, do you ?

An object's speed has no effect whatsoever on its potential energy ... only if it changes the object's height above ground.

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A package is dropped from a hovering helicopter.

aivan3 [116]

Answer:

The height of the package when it was released was 1102.5 meters

Explanation:

A package is dropped from a hovering helicopter

Dropped means the initial velocity of the package is zero

The package takes 15 seconds to strike the ground

Ignore the air resistance

We need to know the height of the package when it was released

$h=ut+\frac{1}{2}gt^{2}$ , where h is the height of the package

from the ground, u is the initial velocity, g is the acceleration of gravity

and t is the time

u = 0 , t = 15 seconds , g = 9.8 m/s²

$h=(0)(15)+\frac{1}{2}(9.8)(15)^{2}$

$h=0+1102.5$

h = 1102.5 meters

<em>The height of the package when it was released was 1102.5 meters</em>

4 0

3 years ago

Thank you so muchhhhh

padilas [110]

Answer:

c. the rotation and revolution of the moon are the same as the earth

Explanation:

that we only see one side of the moon because the moon rotates around the Earth at the exact same speed as it rotates around its own axis, so that the same side of the moon is constantly facing the surface of the earth.

6 0

3 years ago

Read 2 more answers

How do two positive electric charges react to each other?

vodka [1.7K]

Answer:

The two positive electric charges repel each other. If a positive charge and a negative charge interact, their forces act in the same direction, from the positive to the negative charge. As a result opposite charges attract each other: The electric field and resulting forces produced by two electrical charges of opposite polarity.

Explanation:

Hope this helps!

-PBvibes

3 0

3 years ago

Read 2 more answers

A 1.65 kg mass stretches a vertical spring 0.260 m If the spring is stretched an additional 0.130 m and released, how long does

Irina-Kira [14]

Answer:

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

Explanation:

We notice that block-spring system depicts a Simple Harmonic Motion, whose equation of motion is:

$y(t) = A\cdot \cos \left(\sqrt{\frac{k}{m} }\cdot t +\phi\right)$ (1)

Where:

$y(t)$ - Position of the mass as a function of time, measured in meters.

$A$ - Amplitude, measured in meters.

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass of the block, measured in kilograms.

$t$ - Time, measured in seconds.

$\phi$ - Phase, measured in radians.

The spring is now calculated by Hooke's Law, that is:

$k = \frac{m\cdot g}{\Delta y}$ (2)

Where:

$g$ - Gravitational acceleration, measured in meters per square second.

$\Delta y$ - Deformation of the spring due to gravity, measured in meters.

If we know that $m=1.65\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\Delta y = 0.260\,m$ , then the spring constant is:

$k = \frac{(1.65\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{0.260\,m}$

$k = 62.237\,\frac{N}{m}$

If we know that $A = 0.130\,m$ , $k = 62.237\,\frac{N}{m}$ , $m=1.65\,kg$ , $x(t) = 0\,m$ and $\phi = 0\,rad$ , then (1) is reduced into this form:

$0.130\cdot \cos (6.142\cdot t)=0$ (1)

And now we solve for $t$ . Given that cosine is a periodic function, we are only interested in the least value of $t$ such that mass reaches equilibrium position. Then:

$\cos (6.142\cdot t) = 0$

$6.142\cdot t = \cos^{-1} 0$

$t = \frac{1}{6.142}\cdot \left(\frac{\pi}{2} \right)\,s$

$t \approx 0.255\,s$

The system will take approximately 0.255 seconds to reach the (new) equilibrium position.

4 0

3 years ago

What kind of front occurs when a cold air mass replaces a warm air mass?

Andreyy89

Answer:

Explained below:

Explanation:

When a cold air mass meets a warm air mass, a front is formed and if the cold air is replacing the warm air, it is known as a cold front. Cold fronts frequently cause thunderstorms or rain showers because they pressure the air in a steep upward direction at the front's edge. They are also responsible to bring the changes in atmospheric pressure and wind direction.

7 0

4 years ago