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jolli1 [7]
3 years ago
11

What is the Lewis structure of NH3O.

Chemistry
2 answers:
Nat2105 [25]3 years ago
8 0
So, for compound with composition <span>NH3O</span> the correct structure would be <span>H2N−OH</span><span>. The structure of second type is stable for compound </span><span>NOF3</span> and may be observed for amine oxides like (C2H5)3N→O<span> or pyridine-N-oxide.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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DochEvi [55]3 years ago
6 0

Answer :  The Lewis structure of NH_3O is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, NH_3O

As we know that nitrogen has '5' valence electrons, oxygen has '6' valence electrons and hydrogen has '1' valence electron.

Therefore, the total number of valence electrons in NH_3O = 5 + 3(1) + 6 = 14

According to Lewis-dot structure, there are 8 number of bonding electrons and 6 number of non-bonding electrons.

The Lewis-dot structure of NH_3O is shown below.

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Answer:are you there

Explanation:

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3 years ago
What volume will 2.35 moles of nitrogen gas, at STP, occupy?
snow_tiger [21]

Answer:

STP of 1atm and 273 k for pressure

4 0
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A sample of nitrogen gas is stored in a 0.500 L flask at 101.3 atm. The gas is transferred to a 0.750
Paladinen [302]

Answer:

67.5 atm

Explanation:

To answer this problem we can use <em>Boyle's law</em>, which states that at constant temperature the pressure and volume of a gas can be described as:

P₁V₁=P₂V₂

In this case:

P₁ = 101.3 atm

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We input the data:

101.3 atm * 0.500 L = P₂ * 0.750 L

And solve for P₂:

P₂ = 67.5 atm

7 0
3 years ago
A trial of this decomposition experiment, using different quantities of reactants than those listed in the question above produc
Paul [167]

Answer : The volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of O_2 gas = (740-22.4) torr = 717.6 torr

P_2 = final pressure of O_2 gas at STP= 760 torr

V_1 = initial volume of O_2 gas = 280 mL

V_2 = final volume of O_2 gas at STP = ?

T_1 = initial temperature of O_2 gas = 25^oC=273+25=298K

T_2 = final temperature of O_2 gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get:

\frac{717.6torr\times 280mL}{298K}=\frac{760torr\times V_2}{273K}

V_2=242.2mL=0.2422L

Therefore, the volume of O_2(g) produced at standard conditions of temperature and pressure is 0.2422 L

5 0
3 years ago
er solutions can be produced by mixing a weak acid with its conjugate base or by mixing a weak base with its conjugate acid. The
liubo4ka [24]

Answer:

You need to add 19,5 mmol of acetates

Explanation:

Using the Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [base]/[acid]

For the buffer of acetates:

pH = pKa + log₁₀ [CH₃COO⁻]/[CH₃COOH]

As pH you want is 5,03, pka is 4,74 and milimoles of acetic acid are 10:

5,03 = 4,74 + log₁₀ [CH₃COO⁻]/[10]

1,95 = [CH₃COO⁻]/[10]

<em>[CH₃COO⁻] = 19,5 milimoles</em>

Thus, to produce an acetate buffer of 5,03 having 10 mmol of acetic acid, you need to add 19,5 mmol of acetates.

I hope it helps!

7 0
4 years ago
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