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gulaghasi [49]
3 years ago
8

What is not changed when work is done by a machine?

Physics
2 answers:
Irina18 [472]3 years ago
8 0
B) The amount of work done
san4es73 [151]3 years ago
6 0
Your answer is B
hope this helps
:):):):):):):)
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The movement of energy from the sun toward the Earth is an example of A. conduction B. radiation C. convection
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For which planet is the length of the plants day longer than the planets year
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3 years ago
Find average speed when time= 27s and total distance is 94m
Slav-nsk [51]
3.4814815 (or 3 13/27) m/s

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8 0
3 years ago
An AC adapter for a telephone-answering unit uses a transformer to reduce the line voltage of 120 V (rms) to a voltage of 9.0 V.
Illusion [34]

Answer:

1. The number of turns on the secondary output is 18

2. The root mean square power delivered to the transformer is 48 Watts.

Explanation:

A transformer is an electronic device that can be used for increasing or decreasing the value of a given voltage. It consists of primary coils and secondary coil of a definte number of turns. When voltage flows in the primary coil, it induces voltage in the secondary coil. The two types are: step-up and step down transformers.

1. For a given transformer,

          \frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }

where V_{s} is the value of the induced voltage in the secondary coil, V_{p} is he voltage in the primary coil, and N_{s} is the number of turns of the secondary coil, N_{p} is the number of turns in the primary coil.

From the question,

V_{s}  = 9.0 V, V_{p} = 120 V, N_{p} = 240, N_{s} = ?

So that,

           N_{s} = \frac{V_{s}*N_{p}  }{V_{p} }

                = \frac{9 * 240}{120}

               = 18

The number of turns on the secondary output is 18.

2. Power_{rms} = I_{rms} × V_{rms}

                    = 0.4 × 120

                   = 48 W

The rms power delivered to the transformer is 48 Watts.

8 0
3 years ago
A proton is released from rest at the origin in a uniform electric field that is directed in the positive x direction with magni
Vika [28.1K]

Explanation:

It is given that,

Electric field, E=950\ N/C

We need to find the change in the electric potential energy of the proton-field system when the proton travels to x = 2.5 m

From the conservation of energy, the loss in potential energy is equal to the gain in kinetic energy and kinetic energy is is equal to the work done.

W=F\times x

W=q\times E\times x

W=1.6\times 10^{-19}\times 950\times 2.5

W=3.8\times 10^{-16}\ J

So, the change in electric potential energy of the proton field system is 3.8\times 10^{-16}\ J. Hence, this is the required solution.

4 0
3 years ago
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