3 years ago

Given cos0 = 5/6 ans angle 0 is in quadrant 1, what is the exact value of sin 0 in simplest form ?

Mathematics

1 answer:

Maru [420]3 years ago

6 0

Answer:

$\frac{\sqrt{11}}{6}$

Step-by-step explanation:

formula : cos²θ + sin²θ = 1

then sin²θ = 1 - cos²θ

then sin²θ = 1 - (5/6)²

then sin²θ = 1 - 25/36

= (36 - 25)/36

= 11/36

sin²θ = 11/36 ⇒ sinθ = √(11)/6 = =0.552770798393

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