<u>Answer-</u>
The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are
<u>Solution-</u>
Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)
The applying the distance formula,
Two equations are formed because one will be upper from the the given line and other will be below it.
To find 1/10 of a number you need (1/10)*number, or number/10
number/10=0.0003
number=0.0003*10=0.003
How more feet is the outer perimeter of the walkway than the perimeter of the pool is 48 ft
Since 6ft is the width of walkaway
Hence:
Let increase in width be 12
Let increase in length be 12
Now let determine How many
more feet is the outer perimeter of the walkway than the perimeter of the pool
Outer perimeter Number of feets = 2×(12+12)
Outer perimeter Number of feets = 2×24
Outer perimeter Number of feets = 48 ft
Inconclusion How more feet is the outer perimeter of the walkway than the perimeter of the pool is 48 ft
Learn more here:
brainly.com/question/11051185
Answer:
The correct option is;
Between 40 and 50 days
Step-by-step explanation:
The number of seeds that are produced by a plant maturing at age t, S(t), is given as follows;
S(t) = -0.3·t² + 30·t + 0.2
The proportion of plants maturing at age (t) in the plants to be engineered by the geneticist P(t) = 90000/(t + 100)
The number of seeds produced by the plants = S(t) × P(t) = (-0.3·t² + 30·t + 0.2)×(90000/(t + 100))
To find the maximum number of seeds, we differentiate using an online tool, and equate to zero to get;
d((-0.3·t² + 30·t + 0.2)×(90000/(t + 100)))/dt = (-27000·t² - 5400000·t + 269982000)/(t + 100)² = 0
(-27000·t² - 5400000·t + 269982000)/(t + 100)² = 27000(t - 41.419)(t + 241.419)/(t + 100)² = 0
t = 41.419 or t = -241.419
Therefore, in order to maximize the production of seed of the crops of the farmer, the geneticist should select between 40 and 50 days.
