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kogti [31]
3 years ago
11

নিচে ছবি আপলোড করেছি। দয়া করে উত্তর টা দিলে অনেক উপকৃ হতাম।

Mathematics
1 answer:
Paul [167]3 years ago
5 0
I have no Idea what you are saying sorry
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What is the factoring tree for 27
JulsSmile [24]
This is the factor tree check oit the pic to find out

6 0
3 years ago
How many two-digit positive integers can be formed the digits 1,5,6, and 8 if no digit is repeated?
IgorLugansk [536]

Answer:

12

Step-by-step explanation:

There are 4 different digits to choose from. Since we want 2-digit number, we will see what digits can we put in place of 1st digit and what digit can we place in place of 2nd digit.

Hence, <u><em>how many digits (from 1,5,6 and 8) can be placed in the 1st digit of the number we want?</em></u>

Any one of the four digits (1,5,6, or 8).

Now, <em><u>How many digits (from 1,5,6 and 8) can be placed as the 2nd digit of the number we want?</u></em>

Any one of the THREE digits (since repetition is not allowed, we disregard the initial digit).

Thus the number of two-digit positive integers is 4 * 3 = 12

5 0
3 years ago
In an examination 80% students passed. if 15 less have appeared and 10 less have passed, the ratio of passers to failures would
Nina [5.8K]

Answer:

60 students passed, and 75 appeared in examination.

Step-by-step explanation:

Let's say s is the total number of students and p is the number of students who passed.

80% of the students passed, so:

0.8 s = p

If there were 10 less passers, and 15 less students (5 less failures), then the ratio of passers to failures would be 5/1.

(p − 10) / (s − p − 5) = 5 / 1

Simplify the second equation:

p − 10 = 5 (s − p − 5)

p − 10 = 5s − 5p − 25

6p = 5s − 15

Substitute the first equation.

6 (0.8 s) = 5s − 15

4.8 s = 5s − 15

0.2 s = 15

s = 75

p = 0.8 s

p = 60

60 students passed, and 75 appeared in examination.

5 0
3 years ago
Help on college algebra, question is on the picture!
kodGreya [7K]
\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x} is given 
here , \frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x} 
or, \frac{7x^{2} +x +2x-4 }{x(x-2)} = \frac{-4}{ x^{2} -2x}
or,\frac{7 x^{2} +3x-4}{ x^{2} -2x} = \frac{-4}{ x^{2} -2x}
or,7x²+3x-4=-4
or,7x²+3x=0
or,x(7x+3)=0
Either,x=0| Or,7x+3=0
                |or,7x=-3
                |or,x=\frac{-3}{7}
So , the solution set is S={0,-\frac{3}{7}}
8 0
3 years ago
R = -5, s = 2, t = 7, u = -1 <br><br><br> 5r - 4
Doss [256]
5r-4 and r=-5 so it would be 5(-5)=-20, then -4 , so is is -24
8 0
3 years ago
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