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Sergeu [11.5K]
3 years ago
7

Why is this flower able to self-pollinate

Chemistry
1 answer:
Andrei [34K]3 years ago
3 0

Answer:

A flower is self-pollinated if pollen is transferred to it from any flower of the same plant and cross-pollinated if the pollen comes from a flower on a different plant.

Explanation:

This is because each flower is capable of fertilizing itself by autogamy. Autogamy means that the male part of a flower sends pollen to the female part of the same flower.

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Which pairing accurately matches a biomolecules polymer with its monomer subunit
BartSMP [9]
The pairing that accurately matches a bio molecule polymer with its monomer subunit would be B. Protein and amino acids.
6 0
2 years ago
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Which salt is formed by the reaction between hydrochloric acid and sodium hydroxide, write with chemical equation. .​
stepan [7]

Answer:

salt sodium chloride (NaCl)

8 0
3 years ago
6th grade help me plzzzzzz
Anna [14]

Answer:

<h2><u><em>It's protons and neutrons </em></u></h2>

Explanation:

<h2><u><em>Hope this helps </em></u></h2>
3 0
3 years ago
In the following reaction, how many grams of silver can be produced from 49.1 g copper?
notsponge [240]

166.4 g Ag grams of silver can be produced from 49.1 g of copper.

<h3>What is a mole?</h3>

A mole is a very important unit of measurement that chemists use. A mole of something means you have 602,214,076,000,000,000,000,000 of that thing, like how having a dozen eggs means you have twelve eggs.

1 mol Cu + 2 mol AgNO_3 → 2 mol Ag + 1 mol Cu(NO3)2

63.55 g Cu —> 2 x 107.688 g Ag

63.55 g Cu gives 215.376 g of Ag

So, 49.1 g Cu —> \frac{215.376 g X 49.1 g}{63.55 g}

= 166.4 g Ag

Hence, 166.4 g Ag grams of silver can be produced from 49.1 g of copper.

Learn more about moles here:

brainly.com/question/26416088

#SPJ1

5 0
2 years ago
Please Help!
Whitepunk [10]

We can use two equations for this problem.<span>

t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half-life of the element and λ is decay constant.

20 days = 0.693 / λ 
λ   = 0.693 / 20 days        (1) 

Nt = Nο eΛ(-λt)                (2)

Where Nt is atoms at t time, No is the initial amount of substance, λ is decay constant and t is the time taken.
t = 40 days</span>

<span>No = 200 g

From (1) and (2),
Nt =  200 g eΛ(-(0.693 / 20 days) 40 days)
<span>Nt = 50.01 g</span></span><span>

</span>Hence, 50.01 grams of isotope will remain after 40 days.

<span>
</span>

3 0
3 years ago
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