Answer:
a. The balls initial kinetic energy.
Explanation:
As we know that initially speed is given to the ball downwards so that it moved in a circle so then finally reached to point B
Now given that point B is higher than the initial position A from which it is projected
Now by energy conservation we know that
since final speed is zero so we have
so from above equation we can say that since initial kinetic energy is given to the ball so it will be able to reach the point which is higher than its initial position
so correct answer is
a. The balls initial kinetic energy.
Answer:
The amplitude of the resultant wave will be 0.
Explanation:
Suppose the first wave has an amplitude of A. Its angle is given as wt.
The second way will also have the same amplitude as that of first.
After the reflection, a phase shift of π is added So the wave is given as
Adding the two waves give
So the amplitude of the resultant wave will be 0.
The resistance of a conductive wire is given by:
where
is the material resistivity
is the wire length
is the cross-sectional area of the wire
The length of the wire is quadrupled, so if we call L the original length and L' the new length, we can write
Similarly, the radius of the wire is doubled (r'=2r), so the new area is
And if we substitute into the equation, we find that the new resistance of the wire is
Therefore, R=R': this means that the resistance of the wire did not change.
<span>Since the force is applied at an angle from the
horizontal, we will use the horizontal component of this force in calculating
for the displacements.
From derivation, the Fx is:</span>
Fx = F cos φ
Where:
Fx = is the horizontal component of the force
F = total force
φ =
angle in radian = 37 * pi / 180 = 0.645 rad
Calculating: Fx = 30.0 N * cos(0.645)
Fx = 23.97 N = 24 N
Calculating for Work: W = Fx * d
A. W = 24 N * 15 m = 360 N
B. W = 24 N * 16 m = 384 N
C. W = 24 N * 12 m = 288 N
D. W = 24 N * 14 m = 336 N
Answer:
Explanation:
Unstable nucleus tends to emit small particles of matter(alpha or beta particles) with an attendant emission of electromagnetic radiation and some amount of energy.
For every atomic nucleus, there is a specific neutron/proton ratio which ensures stability of the nucleus.
Any nucleus with a neutron/proton combination different from its stability ratio (i.e either too many neutrons or too many protons) will be unstable and split.
The will emit some small particles and radiations until they become stable.
