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Gemiola [76]
3 years ago
13

Are heat lamps are designed to reheat food when food falls under 135 degrees?

Physics
2 answers:
slamgirl [31]3 years ago
7 0
No. The <span>heat lamps are not designed to reheat food when food falls under 135 degrees.

Explanation:
</span>
A heat lamp<span> is an incandescent </span>light bulb<span> that is used for the principal purpose of creating </span>heat<span>. </span>Heat lamps aren't counseled for holding doubtless venturous foods hot at a minimum of one hundred thirty-five degrees Fahrenheit. 
In order to heat up a doubtless venturous food for decent holding the food ought to be cooked-over quickly to a minimum internal temperature of a hundred and sixty-five degrees.
Serjik [45]3 years ago
5 0
That statement is False.

most of them are designed to reheat food when it falls under 165 degrees

hope this helps
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Find an expression for the minimum frictional coefficient needed to keep a car with speed v on a banked turn of radius R designe
solniwko [45]
"v0" means that there are no friction forces at that speed
<span>mgsinΘ = (mv0²/r)cosΘ → the variable m cancels </span>
<span>sinΘ/cosΘ = tanΘ = v0² / gr 
</span><span>Θ = arctan(v0² / gr) </span>

<span>When v > v0, friction points downslope: </span>
<span>mgsinΘ + µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ + µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = ((v²/r)cosΘ - gsinΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>

<span>When v > v0, friction points upslope: </span>
<span>mgsinΘ - µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ - µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = (gsinΘ - (v²/r)cosΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>
4 0
3 years ago
If you know what a JW is LET ME KNOW and it is a type of ppl
lisabon 2012 [21]

Answer:

only thing I think of when I see that is 'Just Wondering'

Explanation:

3 0
3 years ago
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How does the latent heat of fusion of water help slow the decrease in air temperature,perhaps preventing temperatures from falli
love history [14]

Answer:

Water has the ability to release a large amount of energy during the freezing process. All of this energy is released into the air, resulting in a greater movement of air particles that will increase the air temperature. This heat will prevent air temperatures from drastically falling below 0ºC.

Explanation:

The latent heat of water occurs when the water is changing its physical state. In other words, when substances are changing their physical state, the amount of heat calculated for this change is called latent heat, and as we have already said, this heat is not related to the heat exchanges between two systems, but the change of state. physicist.

When water is changing from its liquid state to a solid state, we call latent heat latent heat from fusion (this is because fusion is the name we give to when liquid water is turning to ice). In the process of freezing the page, latent heat releases a large amount of energy into the air near the water. This energy agitates the air molecules, generating heat and preventing the air from reaching temperatures below 0ºC.

6 0
3 years ago
M = 15 kg, a = 2 m/s2, F =
Lisa [10]

Answer:

<h2>30 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 15 × 2

We have the final answer as

<h3>30 N</h3>

Hope this helps you

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3 years ago
Define average velocity.Immersive Reader
vagabundo [1.1K]

Answer:

The slope of a graph of position vs time

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3 years ago
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