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Gemiola [76]
4 years ago
13

Are heat lamps are designed to reheat food when food falls under 135 degrees?

Physics
2 answers:
slamgirl [31]4 years ago
7 0
No. The <span>heat lamps are not designed to reheat food when food falls under 135 degrees.

Explanation:
</span>
A heat lamp<span> is an incandescent </span>light bulb<span> that is used for the principal purpose of creating </span>heat<span>. </span>Heat lamps aren't counseled for holding doubtless venturous foods hot at a minimum of one hundred thirty-five degrees Fahrenheit. 
In order to heat up a doubtless venturous food for decent holding the food ought to be cooked-over quickly to a minimum internal temperature of a hundred and sixty-five degrees.
Serjik [45]4 years ago
5 0
That statement is False.

most of them are designed to reheat food when it falls under 165 degrees

hope this helps
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How many protons does Aluminum have?
Lorico [155]

Answer:

The atomic number of Aluminum is "13"!

Explanation:

The 27 means the atomic mass is 27 . The number of protons plus the number of neutrons is 27. That means the number of neutrons is 27–13=14. Number of neutrons depends on the isotopic form of aluminium.

5 0
3 years ago
Determine the total moment of inertia of a merry-go round with 5 children sitting on it. Of the five children, four are seated a
BaLLatris [955]

Answer:

Explanation:

Given that,

We have five children.

Each of mass m =30kg

They sit on a merry go round

Mass of Merry go round M= 150kg

Radius of Merry go round is r =2m

Four children sit at the edge of the merry go round but one child sit at the centre.

The four child that sit at the edge are 2m from the centre of the merry go round but the one at the centre is 0m from the centre

Moment of inertia?

Moment of inertia is given as

I=Σmi•ri²

For the question, the moment of inertia is the combination of inertial of child and the merry go round

I= I(merry go round) + I(four child)+ I(last child)

The merry go round is assumed to be a solid cylinder, so it is going to have the moment of inertia of solid cylinder

Then,

I(merry go round ) =½ Mr²

Also, Four of the child has the same moment of inertia, they are 2m form the centre of the merry go round why the last child has no moment of inertia

I= I(merry go round) + I(four child) +I(last child )

I= ½Mr² + 4mr² + mr'²

I = ½ × 150 ×2² + 4×30×2² + 30×0²

I = 300 +480+0

I = 780 kgm²

7 0
3 years ago
If you were in a spaceship watching a ball hover at rest (inside the spaceship) in mid-air, and the spaceship suddenly began rap
USPshnik [31]

Answer:

It will still hover until the spaceship "hits" or exerts a force on it.

Explanation:

Remember, if there is no net force, there is no acceleration or movement.

In this case, our ball is hovering in the spaceship, and in space, we can assume there is no F_g, and we can assume there is no F_N, nor no forces acting against it.

So, the ball would not move.

However, once the spaceship starts accelerating, the ball would still hover until the spaceship exerts a force on it.

This is because of the same thing as explained above, no forces acting on it, therefore, no acceleration.

Think about it this way.

Imagine you jumped up, then someone threw a ball at you. Now let's imagine you can't move until you hit the floor, meaning that in an ideal situation only  F_g is acting on you. Now again, let's imagine time slows really down for you, but not the ball. Before the ball comes and hits you, you are "hovering" like a ball. But after the ball hits you, you move a little because the ball exerted a force on you.

If you did not understand what I meant above, just forget about it, and think about the fact that if there is a Net force (all the force values added up), then there is acceleration and movement.

4 0
2 years ago
A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frict
alina1380 [7]

Answer:

The frictional force is  F_f =  1.75 \  N

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  F_N  =  5 \  N

Generally the frictional force that acts on the puck is mathematically represented as

          F_f =  \mu_k  *  F_N

=>       F_f =  0.35  *  5

=>       F_f =  1.75 \  N

3 0
3 years ago
Hat is the approximate pressure of air at sea level?
Tanya [424]
c) 101kPa

Hope I helped! ( Smiles )
5 0
4 years ago
Read 2 more answers
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