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Luden [163]
3 years ago
15

A rock is dropped from a 164-m-high cliff. How long does it take to fall (a) the first 82.0 m and (b) the second 82.0 m

Physics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

Explanation:

Given

Rock is dropped from a height of h=164\ m

Rock is drooped so initial velocity is zero i.e. u=0

Time taken to fall 82\ m is given by

y=ut+\frac{1}{2}at^2

where  

y=displacement

u=initial velocity

a=acceleration

t=time

164=0+\frac{1}{2}gt^2

t=\sqrt{\frac{2\times 82}{9.8}}

t=4.09\ s

Now time taken to fall another 82 m

We can calculate this time by first calculating time taken to cover 82+82 m and then subtracting the time taken to cover 82 m

t_2=\sqrt{\frac{2\times 164}{9.8}}

t_2=5.78\ s

time taken =t_2-t=5.78-4.09=1.69\ s

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