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3 years ago

How does temperature increase?

2 answers:

6 0

Increasing the temperature increases reaction rates because of the disproportionately increase in the number of high energy collisions.
It's only these collisions (possessing at least the activation energy for the reaction)
which results in a reaction!

Lemur [1.5K]3 years ago

4 0

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

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A lorry of mass 12,000kg travelling at a velocity of 2 m/s collides with a stationary car of mass 1500kg. The vehicles move toge

Lubov Fominskaja [6]

Answer:

Approximately $1.8\; \rm m \cdot s^{-1}$ . Assumption: the friction between the two vehicles and the ground is negligible.

Explanation:

The momentum $p$ of an object is the product of its mass $m$ and its velocity $v$ :

$p = m \cdot v$ .

Momentum should be conserved in this collision if there's no external force on these two vehicles. In other words, the sum of the momentum of the lorry and the car should be the same before and after the collision.

Mass of the lorry: $m_1 = 12000\; \rm kg$ .

Velocity of the lorry right before the collision: $2\; \rm m \cdot s^{-1}$ .

Therefore, the momentum of the lorry right before the collision would be $12000\; \rm kg \times 2\; \rm m \cdot s^{-1} = 24000\; \rm kg \cdot m\cdot s^{-1}$ .

Mass of the car: $m_2 = 1500\; \rm kg$ .

Velocity of the car before the collision: $0\; \rm m \cdot s^{-1}$ .

Therefore, the velocity of the car before the collision would be $1500\; \rm kg \times 0\; \rm m \cdot s^{-1} = 0\; \rm kg \cdot m \cdot s^{-1}$ .

Sum of the momentum of the lorry and the car right before the collision:

$24000\; \rm kg \cdot m \cdot s^{-1} + 0\; \rm kg \cdot m \cdot s^{-1} = 24000\; \rm kg \cdot m \cdot s^{-1}$ .

Under the assumption that there is no external forces on the lorry and the car, the sum of the momentum of the lorry and the car right after the collision should also be $24000\; \rm kg \cdot m \cdot s^{-1}$ .

Let $v\; \rm m \cdot s^{-1}$ be the velocity of the lorry and the car after the collision. (The velocity of the two vehicles should be the same because they were moving together.)

Right after the collision, the momentum of the lorry (with a mass of $12000\; \rm kg$ ) would be ${12000\; {\rm kg} \times v\; \rm m \cdot s^{-1}} = 12000\, v \; \rm kg \cdot m \cdot s^{-1}$ .

Similarly, right after the collision, the momentum of the car (with a mass of $1500\; \rm kg$ ) would be ${1500\; \rm kg} \times v\; {\rm m \cdot s^{-1}} = 1500\, v\; \rm m \cdot s^{-1}$ .

The sum of the velocities of the two vehicles right after the collision would be:

$\left(12000\, v \; {\rm kg \cdot m \cdot s^{-1}} + 1500\, v \; {\rm kg \cdot m \cdot s^{-1}}\right)$ .

That quantity should match the momentum right before the collision. In other words:

${12000\; \rm kg \cdot m \cdot s^{-1}} = \left(12000\, v \; {\rm kg \cdot m \cdot s^{-1}} + 1500\, v \; {\rm kg \cdot m \cdot s^{-1}}\right)$ .

Solve this equation for the velocity of the two vehicles after the collision:

$\displaystyle v = \frac{12000}{12000 + 1500}\approx 1.8$ .

Therefore, the velocity of the two vehicles right after the collision would be approximately $1.8\; \rm m \cdot s^{-1}$ .

3 0

3 years ago

As it heats, does fluid rise or compact s

vovangra [49]

Answer: The fluid would rise.

5 0

3 years ago

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A crowbar is used as a lever. The effort force of 40 newtons moves 3 meters. The resistance force of 54 newtons moves 2 meters.

Katyanochek1 [597]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below is the solution:

Output work = 108 J.
Input work = 120 J 

Efficiency = 108/120 = 9/10 = 90% 

(Energy can be converted to heat in friction at the fulcrum, or useless potential energy distorting the crowbar)

6 0

3 years ago

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The average salinity of sea water is A. 3% B. 3.5% C. 2.5% D. 2%

mel-nik [20]

The average salinity of seawater is approximately 3.5%, or 35 per thousand.

8 0

3 years ago

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What is the mass of a crate if a force of 200 N causes it to accelerate at 8 m/s2? (Formula: F=ma)

Ugo [173]

25 kg