Search for 39 05 52.46N 84 30 56.16E and zoom out to an eye altitude of ~30,000 ft. The large-scale structures in this sedimenta
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Answer:
a) The centripetal acceleration of the car is 0.68 m/s²
b) The force that maintains circular motion is 940.03 N.
c) The minimum coefficient of static friction between the tires and the road is 0.069.
Explanation:
a) The centripetal acceleration of the car can be found using the following equation:
Where:
v: is the velocity of the car = 51.1 km/h
r: is the radius = 2.95x10² m
Hence, the centripetal acceleration of the car is 0.68 m/s².
b) The force that maintains circular motion is the centripetal force:
Where:
m: is the mass of the car
The mass is given by:
Where P is the weight of the car = 13561 N
Now, the centripetal force is:
Then, the force that maintains circular motion is 940.03 N.
c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:
Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.
I hope it helps you!
Answer:
6.5 m
Explanation:
First of all, we need to compute the acceleration of the skier. We know that there is only force acting on the skier: the force of friction, which is in the opposite direction to the motion of the skier. Using 2nd Newton Law:
where is the force of friction, with
is the coefficient of kinetic friction
m is the mass of the skier
is the acceleration due to gravity
Re-arranging the equation, we find:
So now we can use the following SUVAT equation to calcualte the total displacement of the skier before stopping:
where
v = 0 is the final velocity
u = 5.30 m/s is the initial velocity
a = -2.16 m/s^2 is the acceleration
d = ? is the displacement
Solving the formula for d, we find: