<span>The vertical axis represents the velocity of the object</span>
Answer:
Kinetic energy is maximum when the player hits the ball.
Explanation:
Kinetic energy
, where m is the mass and v is the velocity.
So kinetic energy is proportional to square of velocity.
Velocity is maximum when the player hits the ball.
So kinetic energy is maximum when the player hits the ball.
I DONT know FiGURE it out YOURSELF
Answer:
Part a)
![a = 1260.3 m/s^2](https://tex.z-dn.net/?f=a%20%3D%201260.3%20m%2Fs%5E2)
Part b)
Direction = upwards
Explanation:
When ball is dropped from height h = 4.0 m
then the speed of the ball just before it will strike the ground is given as
![v_f^2 - v_i^2 = 2 a d](https://tex.z-dn.net/?f=v_f%5E2%20-%20v_i%5E2%20%3D%202%20a%20d)
![v_1^2 - 0^2 = 2(9.81)(4.0)](https://tex.z-dn.net/?f=v_1%5E2%20-%200%5E2%20%3D%202%289.81%29%284.0%29)
![v_1 = 8.86 m/s](https://tex.z-dn.net/?f=v_1%20%3D%208.86%20m%2Fs)
Now ball will rebound to height h = 2.00 m
so the velocity of ball just after it will rebound is given as
![v_f^2 - v_i^2 = 2 a d](https://tex.z-dn.net/?f=v_f%5E2%20-%20v_i%5E2%20%3D%202%20a%20d)
![0 - v_2^2 = 2(-9.81)(2.00)](https://tex.z-dn.net/?f=0%20-%20v_2%5E2%20%3D%202%28-9.81%29%282.00%29)
![v_2 = 6.26 m/s](https://tex.z-dn.net/?f=v_2%20%3D%206.26%20m%2Fs)
Part a)
Average acceleration is given as
![a = \frac{v_f - v_i}{\Delta t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv_f%20-%20v_i%7D%7B%5CDelta%20t%7D)
![a = \frac{6.26 - (-8.86)}{12.0 \times 10^{-3}}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B6.26%20-%20%28-8.86%29%7D%7B12.0%20%5Ctimes%2010%5E%7B-3%7D%7D)
![a = 1260.35 m/s^2](https://tex.z-dn.net/?f=a%20%3D%201260.35%20m%2Fs%5E2)
Part B)
As we know that ball rebounds upwards after collision while before collision it is moving downwards
So the direction of the acceleration is vertically upwards