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topjm [15]
3 years ago
8

Which determines the reactivity of an alkali metal? A. its boiling and melting points B. the shininess of its surface C. the num

ber of protons it has D. its ability to lose electrons
Physics
2 answers:
Naddik [55]3 years ago
7 0

Answer:

D

Ex plane

I just took the test

Gekata [30.6K]3 years ago
4 0

Answer:

D

Please let me know if this helped! Please rate it the brainlist if possible, thanks

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The momentum of an object is given by the product between its mass and its velocity:
p=mv
where m is the mass and v the velocity.

For the object in our problem, m=10 kg and v=10 m/s, therefore its momentum is
p=mv=(10 kg)(10 m/s)=100 kg m/s
So, the correct answer is B).
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Both conduction and convection require matter to transfer heat. ... Convection occurs when warmer areas of a liquid or gas rise to cooler areas in the liquid or gas. Cooler liquid or gas then takes the place of the warmer areas which have risen higher. This results in a continuous circulation pattern.

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3 years ago
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An astronomer studies an image taken by a satellite in space and sees an area of gas, dust, and many stars distributed along spi
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3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 500 rev/s. If such a star has a radius of 17
Alexus [3.1K]

Answer:

7.22 × 10²⁹ kg

Explanation:

For the material to be in place, the gravitational force on the material must equal the centripetal force on the material.

So, F = gravitational force = GMm/R² where M = mass of neutron star, m = mass of object and R = radius of neutron star = 17 km

The centripetal force F' = mRω² where R = radius of neutron star and ω  = angular speed of neutron star

So, since F = F'

GMm/R² = mRω²

GM = R³ω²

M = R³ω²/G

Since ω = 500 rev/s = 500 × 2π rad/s = 1000π rad/s = 3141.6 rad/s = 3.142 × 10³ rad/s and r = 17 km = 17 × 10³ m and G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

Substituting the values of the variables into M, we have

M = R³ω²/G

M = (17 × 10³ m)³(3.142 × 10³ rad/s)²/6.67 × 10⁻¹¹ Nm²/kg²

M = 4913 × 10⁹ m³ × 9.872 × 10⁶ rad²/s²/6.67 × 10⁻¹¹ Nm²/kg²

M = 48,501.942 × 10¹⁵ m³rad²/s² ÷ 6.67 × 10⁻¹¹ Nm²/kg²

M = 7217.66 × 10²⁶ kg

M = 7.21766 × 10²⁹ kg

M ≅ 7.22 × 10²⁹ kg

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2 years ago
A greenhouse is an example of a(n) __________________________________. Question 7 options: active solar energy system. biomass g
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