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galben [10]
3 years ago
7

What is the formula for finding Δt?

Physics
1 answer:
natita [175]3 years ago
5 0

Answer:

☆<《<em><u>HOPE IT WILL HELP YOU</u></em><em><u> </u></em>》>☆

Explanation:

The formula for finding TRIANGLE is Half + Base × Hight

<h2 /><h2>H+B×H</h2>

<h3>please mark my ans as BRAIN LIST</h3>

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Explain how power is determined within the context of electricity/circuitry.
nalin [4]
In the context of electricity the equation for power would be as follows:

V*I=W
The V stands for voltage. The I stands for current. The W stands for power.
The reason why power is symbolized by "W" is because it was named after James Watts.

8 0
3 years ago
How far something moves in a specific amount of time
Svetlanka [38]
Distance is how far something moves in a specific amount of time. 
5 0
3 years ago
Read 2 more answers
Find a) molar fraction, b) concentration in mol / and c) concentration in mol / kg of an aqueous solution with 25% alcohol: the
igor_vitrenko [27]

Explanation:

Answer

( 58.3 mL ) (

0.789 g

1 mL

) (

1 mole

46 g

) = 1 mole C2H5OH

( 500 mL H2O ) (

1 g

1 mL

) (

1 mole

18 g

) = 27.8 mole H2O

The total moles = 1 mole C2H5OH + 27.8 mole H2O = 28.8 moles

The mole fraction =

moles C2H5OH

total moles

=

1 mole C2H5OH

28.8 total moles

= 0.035

The mole percent would be 3.5%.

What is the weight fraction?

Answer

( 58.3 mL ) (

0.789 g

1 mL

) = 46 g C2H5OH

( 500 mL H2O ) (

1 g

1 mL

) = 500 g H2O

The total mass = 46 g C2H5OH + 500 g H2O = 546 g

The mass fraction =

mass C2H5OH

total mass

=

46 g C2H5OH

546 total grams

= 0.084

The mass percent would be 8.4%.

What is the molarity?

Answer

The molarity =

moles C2H5OH

L of solution

=

1 mole C2H5OH

.5583 L

= 1.79 M

What is the molality?

Answer

The molality =

moles C2H5OH

kg of solvent

=

1 mole C2H5OH

0.5 kg H2O

= 2

8 0
3 years ago
If two bodies have the same kinetic energy do they have the same momentum or not and why?
Mnenie [13.5K]
They do because if one thing is moving and the is there both moveing in once
6 0
3 years ago
An isotropic point source emits light at wavelength 510 nm, at the rate of 170 W. A light detector is positioned 410 m from the
Wewaii [24]

Answer:

\frac{dB}{dt} = 3.03 \times 10^6 T/s

Explanation:

As we know that the power emitted by the source is given as

P = 170 W

now we know that

P = \frac{N}{t} (\frac{hc}{\lambda})

now we know that energy density is given as

u = \frac{B^2}{2\mu_0} + \frac{\epsilon_0 E^2}{2}

now we have

E = B c

u = \frac{B^2}{2\mu_0}

intensity is defined as

I = \frac{P}{A}

now we have

\frac{I}{c} = u = \frac{B^2}{2\mu_0}[/tex]

now we have

\frac{dB}{dt} = \omega B

\frac{dB}{dt} = \frac{2\pi c B}{\lambda}

\frac{dB}{dt} = \frac{2\pi c \sqrt{2\mu_0 I}}{\lambda\sqrt c}

here we have

I = \frac{P}{4\pi r^2}

I = \frac{170}{4\pi (410)^2}

I = 8.05 \times 10^{-5}

now we have

\frac{dB}{dt} = \frac{2\pi\sqrt{2\mu_0 c (8.05 \times 10^{-5})}}{(510 nm)}

\frac{dB}{dt} = 3.03 \times 10^6 T/s

4 0
3 years ago
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