Answer:
<h3>B. 19miles</h3>
Explanation:
If Freddy drives 4 miles east to his friend's house. He then travels 9 more miles east to the supermarket. Finally on his way back home he out of gas 6 miles after leaving the supermarket, the distance travel by fred will be the sup of all the distances he covered throughout the journey.
Distance covered by fred = 4miles + 9miles + 6miles
Distance covered by fred = 13miles + 6miles
Distance covered by fred = 19miles
Answer:
D. 15 m/s downward
Explanation:
v = at + v₀
v = (-9.8 m/s²) (1.5 s) + (0 m/s)
v = -14.7 m/s
Rounded to two significant figures, the answer is D, 15 m/s downward.
I'm going to assume that this gripping drama takes place on planet Earth, where the acceleration of gravity is 9.8 m/s². The solutions would be completely different if the same scenario were to play out in other places.
A ball is thrown upward with a speed of 40 m/s. Gravity decreases its upward speed (increases its downward speed) by 9.8 m/s every second.
So, the ball reaches its highest point after (40 m/s)/(9.8 m/s²) = <em>4.08 seconds</em>. At that point, it runs out of upward gas, and begins falling.
Just like so many other aspects of life, the downward fall is an exact "mirror image" of the upward trip. After another 4.08 seconds, the ball has returned to the height of the hand which flung it. In total, the ball is in the air for <em>8.16 seconds</em> up and down.
Current at all points of a series circuit must be the same, because there's no place in the circuit where electrons are being manufactured, and no place where they're leaking out and falling on the floor. The nimber of electrons that leaves the loop is the same number that entered it.
I'm not sure what is nmeant by "p.d. remains different" .
Answer:
Density of liquid = 4730 kg/m³
Atmospheric pressure on planet X = 8401.7 N/m²
Explanation:
Pressure, P = ρgh where ρ = density of liquid, g =9.8 m/s² and h = height of column at earth's surface = 2185 mm. Since P = atmospheric pressure, for mercury, P = ρ₁gh₁ where ρ₁ = 13.6 g/cm³ and h₁ = 760 mm
So, ρgh = ρ₁gh₁
ρ = ρ₁h₁/h = 13.6 g/cm³ × 760/2185 = 4.73 g/cm³ = 4730 kg/m³
The atmospheric pressure on planet X
P = ρg₁h₃ g₁ = g/4 and h₃ = 725 mm = 0.725 m
on planet X
P = ρg₁h₃ = (4730 kg/m³ × 9.8 m/s² × 0.725 m)/4 = 8401.7 N/m²
