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scoray [572]
3 years ago
5

How many grams are there in 3.30x10 23 grams of n2i6

Chemistry
1 answer:
qwelly [4]3 years ago
8 0
Technically, the answer should be 3.30 * 10^23 grams. But I think you mean either molecules, atoms, moles or grams of Ni2I6 with that number of molecules .

1 mole of Ni2 I6  = 6.02 * 10^23 molecules
x  [mole] = 3.30 * 10^23 molecules

1/x = 6.02 * 10^23 / 3.30 * 10^23 Cancel the 10^23 on the right side
1/x = 6.02 / 3.30 Cross multiply
3.30 = 6.02 x Divide by 6.02
3.30 / 6.02 = x 
x = 0.548 moles 

what to do from here?

1 mole of Ni2I6 is
2 * Ni = 2 * 59 = 118 grams
6 *  I = 6 * 131 = <u>786 grams</u>
Total  =               904 grams

Set up a proportion.
<u>1 mole Ni2I6 </u>  = <u>904 grams</u>  
0.548 moles    = x

1/0.548 = 904/x Cross multiply
x = 0.548 * 904
x = 495.4 grams of Ni2I6 <<<<<< Answer.

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Answer:

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Explanation:

Density = mass/ volume

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7 0
3 years ago
For the reaction a2 + b2 → 2ab, ea(fwd) = 105 kj/mol and ea(rev) = 77 kj/mol. assuming the reaction occurs in one step, calculat
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Answer is: 28 kJ.
Chemical reaction: A₂ + B₂ ⇄ 2AB.
Ea(forward) = 105 kJ/mol.
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</span>ΔH(reaction) = Ea(forward) - Ea(reverse).
ΔH(reaction) = 105 kJ/mol - 77 kJ/mol.
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