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LenKa [72]
3 years ago
6

How does fouling affects the performance of a heat exchanger?

Engineering
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

Fouling :

  When rust or undesired material deposit in the surface of heat exchanger,is called fouling of heat exchanger.

Effect of heat exchanger are as follows"

1.It decreases the heat transfer.

2.It increases the thermal resistance.

3.It decreases the overall heat transfer coefficient.

4.It leads to increase in pressure drop.

5.It increases the possibility of corrosion.

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Write a Python program that does the following. Create a string that is a long series of words separated by spaces. The string i
dybincka [34]

Answer:

The code is attached.

Explanation:

I created a string s including 6 colors with spaces in between. Then I converted the string into a list x by using split() method. I used three different methods for removing elements from the list. These methods are remove(), pop() and del.

\\ Then I used methods append(), insert() and extend() for adding elements to the list.

\\ Finally I converted list into a string using join() and adding space in between the elements of the list.

4 0
4 years ago
Please help me with this. Plzzz.
Drupady [299]

Answer:

450,000m = 450km = 4.5E5

32,600,000W = 32.6MW = 3.26E7

59,700,000,000cal = 59.7Gcal = 5.97E10

0.000000083s = 83ns = 8.3E-8

35,000Ω = 35kΩ = 3.5E4

Explanation:

Giga   = 1,000,000,000

Mega = 1,000,000

kilo     = 1,000

unit    = 1

deci   = .1

centi  = .01

milli    = .001

micro = .000001

nano = .0000000001

pico  = .000000000001

You should be able to look at these and convert between them in seconds if you want to pursue anything in engineering.

7 0
3 years ago
Document the XSS stored exploit script: Use the View Source feature of the web page and create a screenshot of the few lines cod
Natali [406]

Answer:

Hold on let me ask my brother

Explanation:

5 0
3 years ago
A cylindrical brass rod has a length of 5.00cm extending from a holder and a diameter of 4.50mm. Its Young's modulus is 98.0GPa.
Galina-37 [17]

Answer:

elongation of the brass rod is 0.01956 mm

Explanation:

given data

length = 5 cm = 50 mm

diameter = 4.50 mm

Young's modulus = 98.0 GPa

load = 610 N

to find out

what will be the elongation of the brass rod in mm

solution

we know here change in length formula that is express as

δ = \frac{PL}{AE}    ................1

here δ is change in length and P is applied load  and A id cross section area and E is Young's modulus and L is length

so all value in equation 1

δ = \frac{PL}{AE}  

δ = \frac{610*50}{\frac{\pi}{4} * 4.50^2 * 98*10^3}  

δ = 0.01956 mm

so elongation of the brass rod is 0.01956 mm

7 0
3 years ago
A home electrical system is joined to the electric company's system at the junction of the
aleksandrvk [35]

That would be B, I hope this helps!

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