The equatorial diameter of the earth is 12,756 km.
Therefore the equatorial radius is
r = 12756/2 = 6378 km.
The angular velocity of the earth is
ω = (2π radians)/(24 hours) = 0.2618 rad/h
The tangential velocity of a person at the equator is
v = rω
= (6378 km)*( 0.2618 rad/h)
= 1670 km/h
Answer: 1670 km/h
I hope this helps you.
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Answer:HI! Just listen to the explanation
Explanation:
So, to create the storyboard, you need to make boxes that resemble what you see in comics and fill them in with process of how the shipment would work.
All you need to do is describe how the shipment works! :) If it seems hard to get the word count in, just ask your supervisor to shorten the word count slightly to make it as easy as possible!!! I hope this really helped and made it easier on you! Good luck to everyone working on this assignment!!! ;)
Answer:
The depth to which the cage will drop for each single rotation of the drum is approximately 18.85 m.
Explanation:
The mine winch drum consists of a drum around around which the haulage rope is attached
Therefore, given that the diameter of the winch drum = 6 m
The length of rope unwound by each rotation = How far the cage will drop for each single rotation of the drum
The length of the rope unwound by each rotation = The rope that goes round the circumference of the winch drum, once
∴ Since the rope that goes round the circumference of the winch drum, once = The circumference of the winch drum, we have;
The length of the rope unwound by each rotation = The circumference of the winch drum = π × The diameter of the winch drum
The length of the rope unwound by each rotation = π × 6 m = 6·π m
The length of rope unwound by each rotation = How far the cage will drop for each single rotation of the drum = 6·π m
How far the cage will drop for each single rotation of the drum = 6·π m ≈ 18.85 m
The depth to which the cage will drop for each single rotation of the drum ≈ 18.85 m.