Answer:
8.65x10 7 grams of nacl
Explanation:
There are 6.02x10 23 atoms per one mol
so
8.88x 10 29 x (1/6.02 x 10 23)
Will give us mols of NaCl
to go from mols to grams we multiple mols by molar mass
so
1.48x10 6 mols of Nacl x 58.44 g/mol = 8.65x10 7 grams of nacl which can be converted to
86500 kg
1 ionic, 2 covalent, 3 ionic, 4 ionic, 5 ionic 6ionic, 7 covalent, 8 covalent, 9 acid, 10 ionic, 11 ionic, 12 ionic, 13ionic, 14ionic
To solve this problem, we must assume ideal gas behaviour so
that we can use Graham’s law:
vA / vB = sqrt (MW_B / MW_A)
where,
<span>vA = speed of diffusion of A (HBR)</span>
vB = speed of diffusion of B (unknown)
MW_B = molecular weight of B (unkown)
MW_A = molar weight of HBr = 80.91 amu
We know from the given that:
vA / vB = 1 / 1.49
So,
1/1.49 = sqrt (MW_B / 80.91)
MW_B = 36.44 g/mol
Since this unknown is also hydrogen halide, therefore this
must be in the form of HX.
HX = 36.44 g/mol , therefore:
x = 35.44 g/mol
From the Periodic Table, Chlorine (Cl) has a molar mass of
35.44 g/mol. Therefore the hydrogen halide is:
HCl