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Lyrx [107]
4 years ago
13

Which nuclear emission is negatively charged?

Chemistry
2 answers:
irina [24]4 years ago
5 0
A beta particle is negatively charged
stich3 [128]4 years ago
3 0

The nuclear emission that is negatively charged is \boxed{{\text{2}}{\text{. a beta particle}}}.

Further Explanation:

Radioactive decay:

Also known as nuclear decay, radioactivity, nuclear or radioactive disintegration. It is the process due to which an unstable atomic nucleus releases its energy in the form of various particles such as alpha particles, beta particles, and gamma particles.

Following are the types of radioactive decays:

1. Alpha decay

In this decay, alpha particles are emitted by unstable nuclei. An alpha particle is a helium nucleus with two protons and two neutrons. It has a charge of +2. The general equation for an alpha decay is as follows:

_{\text{Z}}^{\text{A}}{\text{X}} \to _{{\text{Z - 2}}}^{{\text{A - 4}}}{\text{X}} + _{\text{2}}^{\text{4}}{\text{He}}

2. Beta decay

In this decay, beta particles are produced. This occurs when the nucleus decays continuously and emits an electron or a positron. The general equation for beta decay is as follows:

_{\text{Z}}^{\text{A}}{\text{X}} \to _{{\text{Z + 1}}}^{\text{A}}{\text{X}} + _{{\text{ - 1}}}^{\text{0}}{\beta }}

Beta decay is further classified as follows:

(a) {\beta }}^-} decay: In this decay, an electron and an electron antineutrino are emitted. The atomic number of the element is increased by one. Its general equation is as follows:

_{\text{Z}}^{\text{A}}{\text{X}}\to _{{\text{Z+1}}}^{\text{A}}{\text{X}}+{e^-}+{\mathop{\text{v}}\limits^-_{\text{e}}}

(b) {\beta }}^+} decay or positron emission: In this decay, a positron and an electron neutrino are emitted. The atomic number of the element is decreased by one. Its general equation is as follows:

_{\text{Z}}^{\text{A}}{\text{X}} \to _{{\text{Z}} - 1}^{\text{A}}{\text{X}}+{e^+}+{{\text{v}}_{\text{e}}}

3. Gamma decay

In this decay, gamma rays are emitted. Energy is emitted during gamma decay but the number of protons remains unaltered. The general equation for gamma decay is as follows:

_{\text{Z}}^{\text{A}}{\text{X}} \to _{\text{Z}}^{\text{A}}{\text{X}} + _{\text{0}}^{\text{0}}{{\gamma }}

4. Neutron emission

It is the type of radioactive decay that occurs when one or more neutrons are ejected from a nucleus. Neutrons are the subatomic particles with no charge. Since only neutrons are removed from the atom, the number of protons as well electrons remain unaltered. This results in the formation of an isotope of the same element.

Therefore the negatively charged nuclear emission is a beta particle because an electron that is a negatively charged species is lost in {\beta }}^-} decay, a type of beta decay.

Learn more:

1. What nuclide will be produced in the given reaction? brainly.com/question/3433940

2. Calculate the nuclear binding energy: brainly.com/question/5822604

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Nuclear chemistry

Keywords: alpha particle, beta particle, gamma decay, positron, negatively charged, neutron emission, radioactivity, radioactive decay, unstable atomic nucleus.

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4 0
3 years ago
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Hi, please I need help
stellarik [79]

The mass of ethanol (alcohol) = 538.016 g

<h3>Further explanation</h3>

Given

Reaction

C₁₂H₂₂O₁₁(aq)+H₂O(I) = CH₃CH₂OH(aq)+CO₂(g)

1 kg of sugar = 1000 g

Required

The mass of ethanol

Solution

Balanced equation

C₁₂H₂₂O₁₁(aq)+H₂O(I) = 4CH₃CH₂OH(aq)+4CO₂(g)

mol of sugar (MW = 12.12+22.1+11.16=342 g/mol) :

mol = mass : MW

mol = 1000 g : 342 g/mol

mol = 2.924

From the equation, mol ratio of C₁₂H₂₂O₁₁ : CH₃CH₂OH = 1 : 4, so mol ethanol =

= 4 x mol sugar

= 4 x 2.924

= 11.696

Mass of ethanol(MW=46 g/mol) :

mass = mol x MW

mass = 11.696 x 46

mass = 538.016 g

5 0
3 years ago
H2 how many elements?
rjkz [21]
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4 0
3 years ago
1) A box has a mass of 8 kg and a volume of 2 m? What is its density? |
pentagon [3]

\huge\boxed{4\ \text{kg/m$^3$}}

We know that \rho=m\div V, where \rho is density, m is mass, and V is volume.

Substitute in the values we know and solve:

\begin{aligned}\rho&=8\div2\\&=\boxed{4}\end{aligned}

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3 years ago
What mass of powdered drink mix is needed to make 0.5 M solution of 100 ml
Vladimir [108]

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

Step 1 : Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1   =  x /0.1    ⇒ 0.5* 0.1  = x = 0.05 M

This means there is 0.05 mol per 100mL

e

Step 2 : calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

0.05 mol = mass / 342.2965 g/mol

To find the mass, we isolate it ⇒0.05 mol * 342.2965 g/mol = 17,114825g

There is 17,114825 g of powdered drink mix needed

5 0
3 years ago
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