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3 years ago

Find the force of gravity between two physics students that have masses of 74.0 kg and 82.5 if they are sitting 0.95 m apart

1 answer:

7 0

The force of gravity is calculated by F = G*(m1*m2)/r^2. Here m1 = 74 kg, m2 = 82.5 kg and r = 0.95 m (and G is 6.674Ă—10â’11 m3â‹…kgâ’1â‹…sâ’2). Plug in and calculate: F = 6.674e-11 * (74*82.5)/(0.95^2) ~ 4.52 e-7 N = 45 ÂµN Answer: the force is 45 ÂµNewtons.

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Air at 25°C and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible

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Answer:

$T_{2} = 25^{\circ}C$

Solution:

As per the question:

Temperature, $T_{1} = 25^{\circ}C$

Pressure, $P_{1} = 5 atm[\tex]Now,We know that the process of throttling occurs in adiabatic conditions where no heat is transferred in between the system and the surrounding, i.e., Q = 0Thus no work is done in this process, i.e., W = 0Enthalpy also remains same from one state to the other state, i.e., [tex]\Delta h = 0$

Therefore, from the eqn:

$Q - W = \Delta h + \Delta KE$

We can write:

$\Delta h = h_{1} - h_{2} = 0$

$\Delta h = C_{p}\Delta T$

$C_{p}(T_{2} - T_{1}) = 0$

Thus

$T_{1} = T_{2} = 25^{\circ}C$

where

$T_{2}$ = Exit temperature

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