The distance between object P1 and its image formed is determined as 36 m.
<h3>
Distance of the image</h3>
The distance of the image formed by object P1 is calculated as follows;
In a plane mirror; object distance = image distance
image distance of P1 = 18 m
distance between object and image = 18m + 18 m = 36 m
Thus, the distance between object P1 and its image formed is determined as 36 m.
Learn more about plane mirrors here: brainly.com/question/1126858
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Answer: B 100 J
Explanation: Pic Attached. Hope This Helps.
Answer:
636.4 J
Explanation:
The potential energy between one of the charges at the corner of the square and the fifth identical charge is U = kq²/r where q = charge = +50 × 10⁻⁶ C and r = distance from center of square. = √2 m (since the midpoint of the sides = 1 m, so the distance from the charge at the corner to the center is thus √(1² + 1²) = √2)
Since we have four charges, the additional potential energy to move the charge to the centre of the square is U' = 4U = 4kq²/r
U' = 4kq²/r
= 4 × 9 × 10⁹ Nm²/C² (+50 × 10⁻⁶ C)²/√2 m
= 900 Nm²/√2 m
= 636.4 J
Answer:
option (b)
Explanation:
B = 0.7 x 10^-4 T
v = 940 km/h = 940 x 5 / 18 = 261.11 m /s
l = 60 m
Th emotional emf is given by
e = B v l
e = 0.7 x 10^-4 x 261.11 x 60 = 1.096 V
e = 1.1 V
