What mass of lead (density 11.4 g/cm3) would have an identical volume to 28.5 g of mercury (density 13.6 g/cm3)?

1 answer:

6 0

The density of a material is its unique property which is different for different substances. The volume or mass of a compound can be determined from the other given mass of a compound, if the density of both the material is available. We know density of a material is equal to the mass per unit volume. From the given data 13.6 g of mercury has 1 cm³ volume. Thus 28.5g of mercury will have $\frac{28.5}{13.6}=2.095$ cm³ volume. Now as per the given density value of lead 11.4g of lead has 1 cm³ volume. Thus 2.095 cm³ volume of lead has (2.095×11.4)=23.889g.

You might be interested in

I'll give you a cookie

Llana [10]

Answer:

B. Is the correct answer :) i hope this helps!!

Explanation:

brainliest please?

8 0

3 years ago

Read 2 more answers

Answer and work for this problem

MArishka [77]

We can write the balanced equation for the synthesis reaction as
H2(g) + Cl2(g) → 2HCl(g)

We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
mass of H2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol H2 / 2 mol HCl) *
(2.02 g H2 / 1 mol H2)
= 4.056 g H2

We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
(70.91 g Cl2 / 1 mol Cl2)
= 142.4 g Cl2

Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.

6 0

3 years ago

The reaction that is carried out by the enzyme catalase produces __________. The reaction that is carried out by the enzyme cata

Mnenie [13.5K]

Answer:

(a) $H_{2}O$ (b) $CO_{2}$

Explanation:

The reaction that is carried out by the enzyme catalase produces $H_{2} O$

The reaction that is carried out by the enzyme catalase produces $CO_{2}$

6 0

3 years ago

Which type of wave cannot move without a medium in which to travel?

Zanzabum

sound wave cannot travel without a medium.

5 0

3 years ago

using the equation, c5h12 8o2 arrow 5co2 6h2o, if 108 g of water are produced, how many grams of oxygen were consumed?

vfiekz [6]

Molar mass:

H₂O = 18.0 g/mol

O₂ = 32.0 g/mol

C₅H₁₂ + 8 O₂ -> 5 CO₂ + 6 H₂O

8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O

mass O₂ = 108 x 8 x 32 / 6 x 18

mass O₂ = 27648 / 108

mass O₂ = 256 g

hope this helps!

8 0

3 years ago