All categories

2 years ago

According to the chart of specific heats, which material requires the most heat to raise its temperature from 10°C to 30°C?

Chemistry

1 answer:

myrzilka [38]2 years ago

8 0

The material which requires the most heat to raise its temperature from 10°C to 30°C is oil.

<h3>What is the formula to calculate absorbed heat?</h3>

The formula which we used to calculate the amount of involved heat in relation with specific heat is:

Q = mcΔT, where

Q = absorbed heat
m = mass
c = specific heat
ΔT = change in temperature

Among the given materials, specific heat of oil is highest than other materials so will require maximum absorbed heat.

Hence, oil requires the most heat.

To know more about specific heat, visit the below link:

brainly.com/question/6198647

#SPJ1

You might be interested in

What is the difference between glucose and fructose.

CaHeK987 [17]

Answer:

glucose is in large sugar molecules, while fructose is in simple fruits and vegetables

4 0

2 years ago

Read 2 more answers

Lastly, Snape thinks we should try one more calculation. What is the retention factor if the distance traveled by the solvent fr

Neporo4naja [7]

Answer:

0.1 is the retention factor.

Explanation:

Distance covered by solvent , $d_s= 2.0 cm$

Distance covered by solute or ion, $d = 0.20 cm$

Retention factor $(R_f)$ is defined as ratio of distance traveled by solute to the distance traveled by solvent.

$R_f=\frac{d}{d_s}$

$R_f=\frac{0.20 cm}{2.0 cm}=0.1$

0.1 is the retention factor.

7 0

3 years ago

A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati

prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

$k=\frac{2.303}{48.0}\log\frac{53500}{42520}$

$k=9.98\times 10^{-2}hr^{-1}$

Now we have to calculate the half-life.

$k=\frac{0.693}{t_{1/2}}$

$9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}$

$t_{1/2}=6.94hr$

Therefore, the half life of 28-Mg in hours is, 6.94

8 0

3 years ago

Which of these steps is most likely to be part of an investigation about friction?

Serggg [28]

Answer:

I want to say option C: Testing which surfa e is easier to slide a wooden block across.

Explanation:

I'm not 100 % sure though with my answer. I'm truly so very sorry if my answer is wrong. I tried my best.

4 0

3 years ago

How can an electron cloud be compared with a spinning airplane propeller? Both represent objects that move in a circular motion

adelina 88 [10]

The answer is that exact locations within either cannot be determined at any given moment in time.

An electron cloud be compared with a spinning airplane propeller in the manner that in both exact location within either cannot be determined at any given moment in time.

In both electron cloud as well as spinning airplane propeller, there is a probability of finding either but exact location can not be determined.

6 0

3 years ago

Read 2 more answers