Answer:
Energy loss per minute will be ![120\times 10^{26}j](https://tex.z-dn.net/?f=120%5Ctimes%2010%5E%7B26%7Dj)
Explanation:
We have given the star produces power of ![2\times 10^{26}W](https://tex.z-dn.net/?f=2%5Ctimes%2010%5E%7B26%7DW)
We know that 1 W = 1 J/sec
So ![2\times 10^{26}W=2\times 10^{26}J/sec](https://tex.z-dn.net/?f=2%5Ctimes%2010%5E%7B26%7DW%3D2%5Ctimes%2010%5E%7B26%7DJ%2Fsec)
Given time = 1 minute = 60 sec
So the energy loss per minute ![=2\times 10^{26}\times 60=120\times 10^{26}j](https://tex.z-dn.net/?f=%3D2%5Ctimes%2010%5E%7B26%7D%5Ctimes%2060%3D120%5Ctimes%2010%5E%7B26%7Dj)
We multiply with 60 we have to calculate energy loss per minute
It’s procedural memory Bc idk but procedural is how to do something and declarative is remembering something
Explanation:
because the moon has less mass than earth, the force due to gravity at the lunar surface is only about 1/6 that on earthso,the weight of a body on earth is 6×5N =30N
The answer is C.
The Kinetic energy which was exerted and experience pulling the string of a bow is kept as a potential energy at the end of the arrow in contact with the string. Once release from aim at stationary position the potential energy is again transformed.
Answer: Distance is a scalar quantity and direction is not applicable. We can use graphs to depict an object's change in position over time. Create a large number line in the classroom by taping index cards on the floor or wall 1 meter apart.
Explanation: I really hope that was helpful.