For this we need to use several formulas:
v = a*t
This simply means that after 1 second we will have some speed and if we double time, speed will double as well.
But, relation time-traveled distance isn't linear. Traveled distance we calculate:
s = 1/2*a*t^2 we can say that h=s
so if we double time, traveled distance will increase 4 times because of square relation between time and traveled distance.
New traveled distance (h2) will be: h2=4*h
b) Because distance depends on gravity acceleration in free fall h2 will certainly change but the relation h2=4*h will remain the same.
15 yellow bottles.
3 + 7 = 10
50 / 10 = 5
3 x 5 = 15
To develop this problem we require the concepts related to wavelength and its expression to calculate it.
The wavelength is given by

Where,
light velocity
f = frequency.
Our values are given by,



Then,
Visible
Gamma Ray
Infrared
<em>*Note the designation on the type of rays that are, can be found in consulted via On-line or in the optical books referring to the electromagnetic spectrum table with their respective ranges.</em>
Answer:


Explanation:
Given:
- flow rate of water,

<em>∵Density of water is 1 kg per liter</em>
∴mass flow rate of water, 
- height of pumping,

- efficiency of motor drive,

- diameter of pipe,

<u>Now the power required for pumping the water at given conditions:</u>



<u>Hence the electric power required:</u>



<u>Flow velocity is given as:</u>

where: a = cross sectional area of flow through the pipe


Answer:
Chemical energy to electrical energy
Explanation:
In nature, there are several types of energy.
In this example (a flashlight being turned on), we have a conversion of energy from chemical energy to electrical energy. In fact:
- Chemical energy is the energy stored in the chemical bonds of the molecules of the substances used inside the battery. When the chemical reaction inside the battery occurs, this energy is liberated, and it is used to "push" the electrons along the circuit connected to the battery
- Electric energy is the energy associated to the motion of the electrons along the circuit of the flashlight; it is the energy associated to an electric current.
Moreover, in the flashlight the electric energy is then converted into two more types of energy: light energy (since the bulb in the flashlight produces light) and heat energy (because the flashlight also produces heat, so thermal energy).