Answer:
The answer is Pascal or Pa.
<span>a. We can find the velocity when the camera hits the ground.
v^2 = (v0)^2 + 2ay = 0 + 2ay
v = sqrt{ 2ay }
v = sqrt{ (2)(3.7 m/s^2)(239 m) }
v = 42 m/s
The camera hits the ground with a velocity of 42 m/s
b. We can find the time it takes for the camera to hit the ground.
y = (1/2) a t^2
t^2 = 2y / a
t = sqrt{ 2y / a }
t = sqrt{ (2)(239 m) / 3.7 m/s^2 }
t = 11.4 seconds
It takes 11.4 seconds for the camera to hit the ground.</span>
Answer:
x = -6.5 meters
Explanation:
The position of a ball as a function of time t is given by :
..................(1)
Where t is time in seconds
We need to find the position of the ball at 1.9 s. It can be simply calculated putting t = 1.9 s in equation (1) as :
x = -6.5 meters
So, the position of the ball at 1.9 seconds is -6.5 meters. Hence, this is the required solution.
It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s
<u>Explanation:</u>
v = u + at
68.6 ms^-1 = 0 ms^-1 + (9.8 ms^-2 x t)
t = 68.6 ms^-1 / 9.8 ms^-2
t = 7.0s
It takes 7.0s for a piece of wood to be falling from a tall building in the velocity of 68.6 m/s