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shepuryov [24]
3 years ago
6

What happens to the current in a circuit if a 1.5 volt battery

Physics
1 answer:
Alexus [3.1K]3 years ago
4 0

Answer:

the current will improve in performance and tell me if im correct

You might be interested in
A stuntman with a mass of 80.5 kg swings across a moat from a rope that is 11.5 m. At the bottom of the swing the stuntman's spe
wel

Answer:

  • No
  • 5.49 m/s

Explanation:

The net force required to accelerate the stuntman in a circular arc of radius 11.5 m will be ...

  F = mv²/r . . . . where this m is the mass being accelerated, v is the tangential velocity, and r is the radius.

Here, the net force needs to be ...

  F = (80.5 kg)(8.45 m/s)²/(11.5 m) . . . . . where this m is meters

  ≈ 499.8175 kg·m/s² = 499.8 N

Gravity exerts a force on the stuntman of ...

  F = mg = (80.5 kg)(9.8 m/s²) = 788.9 kg·m/s² = 788.9 N

Then the tension required in the rope/vine is ...

  499.8 N+788.9 N= 1288.7 N

This is more than the capacity of the rope, so we do not expect the stuntman to make it across the moat.

_____

The allowed net force for centripetal acceleration is ...

  1000 N -788.9 N = 211.1 N

Then the allowed velocity is ...

  211.1 = 80.5v²/11.5

  30.16 = v² . . . .  multiply by 11.5/80.5

  5.49 = v . . . . . . take the square root

The maximum speed the stuntman can have is 5.49 m/s.

_____

<em>Comment on crossing the moat</em>

The kinetic energy at the bottom of the swing translates to potential energy at the end of the swing. At the lower speed, the stuntman cannot rise as high, so will traverse a shorter arc. At 8.45 m/s, the moat could be about 16.8 m wide; at 5.49 m/s, it can only be about 11.5 m wide.

3 0
4 years ago
A 80.0-kg airplane pilot pulls out of a dive by following, at a constant speed of 180km/hr, the arc of a circle whose radius is
wolverine [178]

Answer: 8.33m/s²

Explanation:

Mass of the airplane pilot = 80kg

The speed of plane v = 180km/h = 50m/s

The radius of circle r = 300 m

The acceleration of the plane will be calculated as:

a = v²/r

a = 50²/300

a = 2500/300

a = 8.33m/s²

Note that 180km/h was converted to m/s by

= (180 × 1000)/(60 × 60)

= 180000/3600

= 50m/s

1000 meters = 1 kilometer

60 minutes = 1 hour

60 seconds = 1 minute

3600 seconds = 1 hour

6 0
3 years ago
Neglect air resistance in this question. If you drop a ball from a height of 4.9 m, it will hit the ground 1s later. If you fire
olchik [2.2K]

Answer:

Explanation:

The time at which an object from from rest depends on air resistance, the height, gravity.

Since the question says we should neglect air resistance and both the ball and the bullet are from the same height they will get to the ground and the same time since they are both fired on earth which has the same gravity..

H=ut+1/2gt^2.

For an object dropping from a height the initial velocity is zero, therefore u=0m/s.

The formula becomes

t=√(2H/g)

So the time and object get to the ground depends on the height from the ground and gravity...

So since no air resistance they will get to the ground together.

7 0
4 years ago
A nerve signal travels 150 meters per second. Determine the number of kilometers that the nerve signal will travel in the same t
joja [24]

Explanation:

It is given that,

A nerve signal travels 150 meters per second. It is the speed of the nerve signal. We need to convert the number of kilometers that the nerve signal will travel in the same time.

We know that,

1 kilometer = 1000 meter

1 hour = 3600 seconds

150\ \dfrac{m}{s}=150\times \dfrac{1/1000\ km}{1/3600\ h}

150\ m/s=540\ km/h

So, the nerve signal will travel at the rate of 540 km/h. Hence, this is the required solution.

6 0
3 years ago
What type of relationship does this graph show?
Schach [20]

Negative because the graph goes down

8 0
4 years ago
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